When 40.0 mL of 0.0800 M Sr(NO3)2 and 80.0 mL of0.0500 M KF are mixed, a precipitate of strontium fluoride (SrF2) is formed. The solubility product Ksp of strontium fluoride in water at 25°C is 2.8 × 10-9. Calculate the [Sr2+] and [F-] remaining in solution at equilibrium.
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When 40.0 mL of 0.0800 M Sr(NO3)2 and 80.0 mL of
0.0500 M KF are mixed, a precipitate of strontium fluoride (SrF2) is formed. The solubility product Ksp of strontium fluoride in water at 25°C is 2.8 × 10-9
. Calculate the [Sr2+] and [F-] remaining in solution at equilibrium.
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