When calculating n how is the value -j +k? I did it and i'm always getting -j +0k which is only -j and that affects the whole process and gets me the wrong answer if possible can someone explain what he did in that step and the steps after it? curl Ê = Sleuri ē )·ñ ds%3DΣThe normal of the planeて=+5where9 = 2-y-5?.0 + 3 (+) +-J +u%3DProjectingxy- plane (z=0)the plane ánds =dy cn2 dy cn.The projecting region *SS eurl ē . n dsSS !-2y A dy derニR= SS (-24) dy chmR is polar fomx = r Cso, y =bing,dy dn= petrede0:07 2n24Flun. of Curl Ēndrdoの= [r.)Auswor : TT Vecter ficld F = ( nCurlE)on= ? (0) -3 (0) +& (1-2y)(-2y) a%3D

This is the problem from vector calculus.

When calculating n how is the value -j +k? I did it and i'm always getting -j +0k which is only -j and that affects the whole process and gets me the wrong answer if possible can someone explain what he did in that step and the steps after it?

When calculating n how is the value -j +k? I did it and i'm always getting -j +0k which is only -j and that affects the whole process and gets me the wrong answer if possible can someone explain what he did in that step and the steps after it?

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter1: Fundamental Concepts Of Algebra

Section1.3: Algebraic Expressions

Problem 20E

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Question

curl Ê = Sleuri ē )·ñ ds
%3D
Σ
The normal of the plane
て=+5
where
9 = 2-y-5
?.0 + 3 (+) +
-J +u
%3D
Projecting
xy- plane (z=0)
the plane án
ds =
dy cn
2 dy cn.
The projecting region *
SS eurl ē . n ds
SS !-2y A dy der
ニ
R
= SS (-24) dy chm
R is polar fom
x = r Cso, y =bing,
dy dn= petrede
0:07 2n
24
Flun. of Curl Ē
ndrdo
の
= [r.)
Auswor : TT

Vecter ficld F = ( n
CurlE)
on
= ? (0) -3 (0) +& (1-2y)
(-2y) a
%3D

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