When calculating the average power delivered to a load by an AC signal, it is not as straight forward as DC. It depends on the difference in phase between the sinusoidal voltage across and current through the load, and it relates to their RMS values. The average power, or sometimes referred to as the active or real power, is related to the underpinning sinusoidal voltage and current by P= Vmg I,mg Cos(Ov-Di) Watts rms rms In this question there is only a resistive load, R: amplitude is 217 V. 16 Q and the Determine the amplitude of the cu through the load I = A Workout the P kW Reset RUN / Stop Electric Potential OPower OCharge R1 160 V1 Simulation Speed 50HZ Charge Flow Power Brightness Current Circuit: 217V resistor, 160 2. A domestic appliance in a certain country draws 560 W of power at unity power factor. The mains voltage is 146 V (rms). Find the peak value of the current.

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.30MCQ: Under balanced operating conditions, consider the three-phase complex power delivered by the...
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When calculating the average power delivered to a load by an AC
signal, it is not as straight forward as DC. It depends on the
difference in phase between the sinusoidal voltage across and
current through the load, and it relates to their RMS values. The
average power, or sometimes referred to as the active or real
power, is related to the underpinning sinusoidal voltage and
current by
P = Vmg I,mg Cos(Ov-Di) Watts
rms
rms
In this question there is only a resistive load, R = 16 N and the
amplitude is 217 V.
Determine the amplitude of the current through the load I
A
Workout the P
kW
Reset
RUN / Stop
Electric Potential
OPower
OCharge
R1
160
V1
Simulation Speed
50HZ
Charge Flow
Power Brightness
Current Circuit
217V
resistor, 160
A domestic appliance in a certain country draws 560 W of power
at unity power factor. The mains voltage is 146 V (rms). Find the
peak value of the current.
Ipk
A
Transcribed Image Text:When calculating the average power delivered to a load by an AC signal, it is not as straight forward as DC. It depends on the difference in phase between the sinusoidal voltage across and current through the load, and it relates to their RMS values. The average power, or sometimes referred to as the active or real power, is related to the underpinning sinusoidal voltage and current by P = Vmg I,mg Cos(Ov-Di) Watts rms rms In this question there is only a resistive load, R = 16 N and the amplitude is 217 V. Determine the amplitude of the current through the load I A Workout the P kW Reset RUN / Stop Electric Potential OPower OCharge R1 160 V1 Simulation Speed 50HZ Charge Flow Power Brightness Current Circuit 217V resistor, 160 A domestic appliance in a certain country draws 560 W of power at unity power factor. The mains voltage is 146 V (rms). Find the peak value of the current. Ipk A
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