When carbon monoxide reacts with hydrogen gas, methane and steam are formed.      CO (g)  +  H 2 (g)  =    CH 4 (g)     +   H 2O (g) At 1127 0 C, analysis at equilibrium shows that the partial pressure of gases are:   CO = 0.921 atm, H 2 = 1. 21 atm,  CH 4 = 0. 0391 atm  and  H 2O = 0.0124 atm. What is equilibrium constant, Kc  for the reaction?

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Q: Hydrogen is prepared commercially by the reaction of methane and water vapor at elevated…

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Q: The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PC|3(g) + Cl2(g) PC|5(g)…

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Q: The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PCl3(g) + Cl2(g) PCl5(g)…

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A: Since you have posted multiple questions, we are entitled to answer the first only.

Q: The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PCl3(g) + Cl2(g) PCl5(g)…

A: The reaction given is PCl3 (g) + Cl2 (g) -------> PCl5 (g)

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Q: The equilibrium constant, K., for the following reaction is 1.29x10 at 600 K. COCl,(g) CO(g) - Cl(g)…

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Q: A student ran the following reaction in the laboratory at 665 K:N2(g) + 3H2(g) 2NH3(g)When he…

A: The given reaction is:

Q: The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PCl3(g) + Cl2(g) PCl5(g)…

A: Given data: PCl3(g)+Cl2(g)→PCl5(g) The equilibrium constant,Kc=83.3 Initial moles of PCl3=0.260 and…

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Q: Hydrogen is prepared commercially by the reaction of methane and water vapor at elevated…

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Q: Consider the following reaction where K. = 77.5 at 600 K. CO(g) + Cl2(g) =COC,(g) A reaction mixture…

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Q: Methanol liquid burns readily in air. One way to represent this equilibrium is: 2 CO2(g) + 4…

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Q: Questiona attached

A: Given reaction,  N2 (g)+ 2O2 (g) ⇔N2O4 (g) The equilibrium constant of the reaction  can be given…

Q: Write the following equilibrium-constant expressions: Kp for 3 Fe(s) + 4 H2O(g) <=> Fe3O4(s) +…

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A: Using Kp =[ PCH4] [PCCl4] / [PCH2Cl2]2

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Q: The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PCl3(g) + Cl2(g) PCl5(g)…

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Q: The equilibrium constant, K., for the following reaction is 1.29x102 at 600 K. COC2(g) CO(g) +…

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A: For the given reaction, the equation for equilibrium constant can be written as above.