When cis-2-decalone is dissolved in ether containing a trace of HCI, an equilibrium is established with trans-2-decalone. The latter ketone predominates in the equilibrium mixture. H H HCI cis-2-Decalone trans-2-Decalone Propose a mechanism for this isomerization and account for the fact that the trans iso- mer predominates at equilibrium.
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- A problem often encountered in the oxidation of primary alcohols to acids is that esters are sometimes produced as by-products. For example, oxidation of ethanol yields acetic acid and ethyl acetate: Propose a mechanism to account for the formation of ethyl acetate. Take into account the reversible reaction between aldehydes and alcohols:Nonconjugated , -unsaturated ketones, such as 3-cyclohexenone, are in an acid-catalyzed equilibrium with their conjugated , -unsaturated isomers. Propose a mechanism for this isomerization.Identify compounds A, B, and C. a. Compound A has molecular formula C8H12 and reacts with two equivalents of H2. A gives HCOCH2CH2CHO as the only product of oxidative cleavage with O3 followed by CH3SCH3. b. Compound B has molecular formula C6H10 and gives (CH3)2CHCH2CH2CHCH3 when treated with excess H2 in the presence of Pd. B reacts with NaNH2 and CH3I to form compound C (molecular formula C7H12).
- Provide a plausible, stepwise mechanism to account for the following transformation. Use curved arrows to depict electron movement, and show all transition states/intermediates.Treatment of cis-4-bromocyclohexanol with HO− affords compound Aand cyclohex-3-en-1-ol. Treatment of trans-4-bromocyclohexanol under the same conditions forms compound B and cyclohex-3-en-1-ol. A and Bcontain different functional groups and are not isomers of each other.Propose structures for A and B and offer an explanation for theirformation.Identify compounds A, B, and C. a.) Compound A has molecular formula C8H12 and reacts with two equivalents of H2. A gives HCOCH2CH2CHO as the only product ofoxidative cleavage with O3 followed by CH3SCH3. b.) Compound B has molecular formula C6H10 and gives(CH3)2CHCH2CH2CH3 when treated with excess H2 in the presence ofPd. B reacts with NaNH2 and CH3I to form compound C (molecularformula C7H12).
- The Stork reaction is a condensation reaction between an enamine donor and an α,β-unsaturated carbonyl acceptor. The overall reaction consists of a three-step sequence of formation of an enamine from a ketone, Michael addition to an α,β-unsaturated carbonyl compound, and hydrolysis of the enamine in dilute acid to regenerate the ketone. Consider the Stork reaction between cyclohexanone and propenal Draw the structure of the product of the enamine formed between cyclohexanone and dimethylamine. - Michael addition to an α,β-unsaturated carbonyl compound, and - hydrolysis of the enamine in dilute acid to regenerate the ketone.Ethyl acetoacetate reacts with ethylene glycol to give Ethyl acetoacetate ethylene glycol ketal and water. In addition to the providing a mechanism for the protection of ethyl acetoacetate, propose a synthesis scheme to prepare 1,1-diphenyl-1-hydroxy-3-butanone from the protected ethyl acetoacetate. Include a mechanism for the final deprotectionstep.Explain this observation: Ethyl 3-phenylpropanoate (C6H5CH2CH2CO2CH2CH3) reacts with electrophiles to afford ortho- and para-disubstituted arenes, but ethyl 3-phenylprop-2-enoate (C6H5CH=CHCO2CH2CH3) reacts with electrophiles to afford meta- disubstituted arenes.
- The reaction of 3,4-dimethyl-3-hexanol (3,4-dimethylhexan-3-ol) with HBr generates compound A as the major product. Treatment of compound A with a strong base gives two isomers of compound B as the major product, along with one isomer of compound C and one isomer of compound D as minor products, all of which have one double-bond equivalent. Identify compounds A, B, C, and D and give their names. By what mechanism does the reaction of 3,4-dimethyl-3-hexanol with HBr occur? By what mechanism does the reaction of A with strong base to form B occur? Propose reaction conditions for an alternative, one-step method for converting 3,4-dimethyl-3-hexanol directly to compound B.The Stork reaction is a condensation reaction between an enamine donor and an α,β-unsaturated carbonyl acceptor. The overall reaction consists of a three-step sequence of formation of an enamine from a ketone, Michael addition to an α,β-unsaturated carbonyl compound, and hydrolysis of the enamine in dilute acid to regenerate the ketone. Consider the Stork reaction between acetophenone and 3-buten-2-one. Draw the structure of the product of the enamine formed between acetophenone and pyrrolidine. Draw the structure of the Michael addition product. Draw the structure of the final product.Two isomers, A and B, of molecular formula C5H8 undergo catalytic hydrogenation with hydrogen gas and palladium on carbon to form the same C5H10 product. On ozonolysis followed by treatment with hydrogen peroxide (H2O2), isomer A gave a product of molecular formula C5H8O4 that has two carboxylic acid groups in it whereas isomer B gave a product of molecular formula C5H8O3 that contains a carboxylic acid group and a ketone group. Which of the following isomeric pairs best match this data?