Question
Asked Nov 1, 2019
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When light of frequency 1.30x 1015 s-1 shines on the surface of cesium metal, electrons are ejected with a maximum kinetic energy of 5.2x 10-19 J. Calculate the wavelength of this light in nm.

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Expert Answer

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Step 1

Electromagnetic spectrum involves different radiations from the lowest to the highest frequency values. Some common radiations which are part of electromagnetic radiations are infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays.

Step 2

The photoelectric effect is the effect of light on the metal surface. Since metals can easily lose their valence electrons hence due to certain frequency of light, the valence electrons come out with certain frequency. The minimum frequency of light that is necessary to eject electron from the metal surface is called as threshold frequency. The maximum kinetic energy of the photoelectrons depended on the frequency of the light. Work function can be defined as the minimum energy required to remove an electron from the surface of the material.

The photoelectric equation involves;

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E hv h the Plank constant 6.63 x 10-34 Js fthe frequency of the incident light in hertz (Hz) =the work function in joules (J) Ek-kinetic energy of the emitted electrons in joules (J)

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Step 3

Calculate the wavelength of light with the help of...

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V = A = V 3.0 x 108 m/sec 1.30 x 105 sec =2.3 x 10 m

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