When the Pb2+ concentration is 1.30 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 2.344V. What is the Mg² concentration? Pb2*(aq) + Mg(s)→ Pb(s) + Mg²*(aq) Answer: M

Principles of Instrumental Analysis
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Chapter22: An Introduction To Electroanalytical Chemistry
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Problem 22.11QAP: Calculate the standard potential for the half-reaction BiOCl(s)+2H++3eBi(s)+Cl+H2O given that Ksp...
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When the Pb2+ concentration is 1.30 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 2.344V. What is the Mg²+
concentration?
*(aq) + Mg(s)– Pb(s) + Mg²*(aq)
Answer:
M
Transcribed Image Text:When the Pb2+ concentration is 1.30 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 2.344V. What is the Mg²+ concentration? *(aq) + Mg(s)– Pb(s) + Mg²*(aq) Answer: M
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