when (x,y)#(0,0) then, of f(x,y) = when (x,y) = (0,0) %3D show that +(x,y) tunetion is continuos at (a,y) = (0,0) %3D

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 78E
icon
Related questions
Question
when (x,y)#(0,0)
then,
of f(a,y) =
when (x,y) = (0,0)
show that +(x,y) funetion is continuos
at (x닝) = (0,0)
Transcribed Image Text:when (x,y)#(0,0) then, of f(a,y) = when (x,y) = (0,0) show that +(x,y) funetion is continuos at (x닝) = (0,0)
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage