Where K = 1.15 x 102  in the equation H2(g) + F2(g) ⇌ 2 HF(g) solve the followinga. When an ICE table is set up and shows the change as some factor of “x,” under what circumstances is “x” so small as to be neglected in calculations (the 5% “rule”). Would that apply to this problem? Make a hypothesis based on the size of K. b. Assume 3.00 moles of all three components are combined in a 1.50 L flask. Show that the equilibrium concentrations of hydrogen and fluorine are both 0.472 M and 5.056 M for hydrogen fluoride. Re-calculate Kusing these values. c. Using the quadratic formula assume 3.00 moles of hydrogen and 6.00 moles of fluorine are introduced into a 3.00 L container. Recalculate K as before and explain why the 5% rule is invalid in this case.

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter12: Solutions
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Where K = 1.15 x 102  in the equation H2(g) + F2(g) ⇌ 2 HF(g) solve the following
a. When an ICE table is set up and shows the change as some factor of “x,” under what circumstances is “x” so small as to be neglected in calculations (the 5% “rule”). Would that apply to this problem? Make a hypothesis based on the size of K.


b. Assume 3.00 moles of all three components are combined in a 1.50 L flask. Show that the equilibrium concentrations of hydrogen and fluorine are both 0.472 M and 5.056 M for hydrogen fluoride. Re-calculate K
using these values.


c. Using the quadratic formula assume 3.00 moles of hydrogen and 6.00 moles of fluorine are introduced into a 3.00 L container. Recalculate K as before and explain why the 5% rule is invalid in this case.

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