Which balanced thermochemical equation corresponds to the standard enthalpy of formation (AHO) of carbon monoxide, CO(g)? The standard enthalpy of formation (AHO) of CO(g) is -110.53 kJ-mol-1 O CO(g) + 1/2O₂(g) →CO₂(g) AHO=-110.53 kJ-mol-1 O 2C(s, graphite) + O₂(g)→2CO(g) AH-110.53 kJ.mol-1 O C(s, graphite) + O₂(g) →CO(g) A H-110.53 kJ.mol-1 O 2CO(g) + O₂(g)→2CO₂(g) AH=-110.53 kJ.mol-1

Chemistry: The Molecular Science
5th Edition
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Author:John W. Moore, Conrad L. Stanitski
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Chapter4: Energy And Chemical Reactions
Section4.10: Standard Formation Enthalpies
Problem 4.18CE
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Which balanced thermochemical equation corresponds to the standard enthalpy of formation (AH₁°)
of carbon monoxide, CO(g)? The standard enthalpy of formation (AH4°) of CO(g) is -110.53 kJ.mol-1
O CO(g) + 1/2O₂(g)→CO₂(g) AH-110.53 kJ-mol-1
O 2C(s, graphite) + O₂(g)→2CO(g)
O C(s, graphite) + 1/2O₂(g) →CO(g)
O 2CO(g) + O₂(g)→2CO2(g) AH = -110.53 kJ.mol-1
AH-110.53 kJ.mol-1
AH = -110.53 kJ.mol-1
Transcribed Image Text:Which balanced thermochemical equation corresponds to the standard enthalpy of formation (AH₁°) of carbon monoxide, CO(g)? The standard enthalpy of formation (AH4°) of CO(g) is -110.53 kJ.mol-1 O CO(g) + 1/2O₂(g)→CO₂(g) AH-110.53 kJ-mol-1 O 2C(s, graphite) + O₂(g)→2CO(g) O C(s, graphite) + 1/2O₂(g) →CO(g) O 2CO(g) + O₂(g)→2CO2(g) AH = -110.53 kJ.mol-1 AH-110.53 kJ.mol-1 AH = -110.53 kJ.mol-1
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