Which equation of a circle has the center, C, and radius, r, as shown in the graph? -3-2 7 T of 7 T -0 C O(x-3)² + (y + 2)² = √26 O(x+3)² + (y-2)² = 26 O(x+3)²+(y-2)² = √26 O(x-3)² + (y + 2)² = 26 26

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section9.5: Systems Of Linear Equations In More Than Two Variables
Problem 42E
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Question
Which equation of a circle has the center, C, and radius, r, as shown in the graph?
-3
-2 -1
6
5
4
3
2
1
0
-3
-5
1
2
C
O(x-3)² + (y + 2)² = √26
O(x+3)² + (y-2)² = 26
O(x+3)2 + (y-2)² = √√26
O(x-3)² + (y + 2)² = 26
3
T =
4 5
√26
6
7
8
9
10
Transcribed Image Text:Which equation of a circle has the center, C, and radius, r, as shown in the graph? -3 -2 -1 6 5 4 3 2 1 0 -3 -5 1 2 C O(x-3)² + (y + 2)² = √26 O(x+3)² + (y-2)² = 26 O(x+3)2 + (y-2)² = √√26 O(x-3)² + (y + 2)² = 26 3 T = 4 5 √26 6 7 8 9 10
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