Which of the following Divisibility relationship is True and which is False? a) 13|78 b) -6 | 24 c) 11 | -33 d) 23 | 96 e) 5 |126
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Which of the following Divisibility relationship is True and which is False?
-
a) 13|78
-
b) -6 | 24
-
c) 11 | -33
-
d) 23 | 96
-
e) 5 |126
Step by step
Solved in 3 steps with 7 images
- Define Accept clause bodySafe Datalog Rule: A Datalog rule is of the form:p :- q1, ..., qn. where n>0 and p is a positive atomic formula and q1, ..., and qn are positive or negative atomic formulas. A positive atomic formula is of the form:r(x1, ..., xm) and a negative atomic formulas of the form:not r(x1, ..., xm) where m>0 and r is a relation name and x1 , ..., xm are either numbers or variables. Relation names and variables are made up of alphabetic letters or digits and start with a lower-case alphabetic letter. Even though the variables are made up of lower and upper-case letters, these should be considered case-insensitive. For example, cno, CNO, cNO, etc all should be treated as the same variable. Some examples of Datalog rules are given below: ancestor(x1, y1) :- parent(x1, y1). teaches(tno,cno) :- faculty(tno), course(cno), assigned(tno,cno). p(x,y) :- q(2,x), r(u,45,z), s(a,b,22). p(x,y,z) :- q(x), not r(y,20), s(x,z). A Datalog rule is considered “Safe” if all variables that appear to the left…87. A relationship should be specified how in the ODL? a. One direction starting with the first class b. One direction starting with the second class c. Neither direction. d. Both directions.
- DATABASE SYSTEMS 6.Any relation that is not part of the logical model, but is made visible to a user as a a)Absolute relation b)Natural relation c)Virtual relation d)Linear relation 7.Which of the following query is correct? a)SELECT ename FROM employee WHERE age>30 and WHERE age <40; b)SELECT ename FROM employee WHERE age>30 and age <40; c)None of these d)SELECT ename FROM employee WHERE age>30 and <40; 8.Produces a relation that contains all the rows of R1, or R2, or both R1 and R2, duplicate tuples being eliminated. R1 and R2 must be union-compatible. a)R1 left outer join R2 b)R1 X R2 c)R1 U R2 d)R1 - R2 9.Find the EmpIds of employees with name and city whose city is either RYK or LHR but empid must be greater than 5 a)SELECT empid, name,city FROM emp WHERE city = 'RYK' AND city ='LHR' AND empid >5); b)SELECT empid, name,city FROM emp WHERE city = 'RYK' OR city ='LHR' AND empid >5); c)SELECT empid, name,city FROM emp WHERE city = 'RYK' OR city ='LHR' OR…Normalize the following from UNF to 3NF. Animal_Adoption (AdoptionID, AdoptionDate, ICNo, FirstName, LastName, Contact, {AnimalID, AnimalName, AnimalType, AnimalRescueDate})Please Provide a detailed explanation and do not copy-paste from others!!! Ret R(x, y, z) be a relation. Write one or more Datalog rules that define ac(R), where C stands for each of the following conditions: a) x = y. b) x < y AND y < z. f) NOT ((x < y OR x < z) AND y< z).
- TASK: Examples of the UNION operator, the use the DISTINCT operator. TOPIC : DATABASEFOOTBALL-PLAYER(CodFP, Name,Surname, Address, CityOfBirth) TEAM(CodT, Name, Category,ConstitutionDate) AWARD(CodA, CodFP, DeliveryDate, DeliveryPlace, Type) PLAYER-TEAM(CodFP, CodT, StartingDate,EndingDate, NumPlayedMatches, NumGoals) Find name, category and constitution date of the teams in which have played (in any time) the players who received, in their career as a whole, the highest number of awards of type “Best goalkeeper”. SELECT distinct T.Name, T.Category, T.CostituitionDate FROM TEAM T, PLAYER-TEAM PT WHERE T.CodFP= PT.CodFP and PT.CodFP IN (SELECT CodFP FROM AWARD D WHERE A.Type = ‘Best goalkeeper’ GROUP BY CodFP HAVING COUNT(*) = SELECT MAX(AwardTot) FROM (SELECT count(*)as AwardTot AWARD A WHERE A.Type = ‘Best goalkeeper’ GROUP BY CodFP) AS TOTAWARDFP i have this solution but im struggling a lot to be…1.Compute the values of the following expressions if x is 1, y is 4 and z is 14. Assume thattrue relations have a value of 1 (I want to see how these problems are worked out) .a. x+5<=z-(x||z)-y b. z/y%z-6<=!y c. x>=1&&y==3+y||z<14 d. x-!y-y<=z*z/6>y
- FileStructure and Database CourseConsider the LIBRARY relational database schema shown in Figure 8.14, which is used to keep track of books, borrowers, and book loans. Referential integrity constraints are shown as directed arcs in Figure 8.14, as in the notation of Figure 5.7. Write down relational expressions also write the queries in SQL statements. for the following queriesFigure 8.18 will be attached a. How many copies of the book titled The Lost Tribe are owned by the library branch whose name is ‘Sharpstown’?c. Retrieve the names of all borrowers who do not have any books checked out.e. For each library branch, retrieve the branch name and the total number of books loaned out from that branch.g. For each book authored (or coauthored) by Stephen King, retrieve the title and the number of copies owned by the library branch whose name is Central.Please what is an independent clause36. In a relation a. Ordering of rows is immaterial b. No two rows are identical c. a and b both are true d. None of these
