Which of the following integrals represents the area of the surface obtained by rotating the curve y = sin (x), 0 < x)/1 + (sin(2) cos(2)" dz ов. 2т sin°(z) /1+ 7/2 O C. 27 7/2 O D. 27 x/1+2 sin(x) cos(x) dx 7/2 O E. 27 z/1+ (2 sin(z) cos(2))° dz 7/2 O F. 27 x/1+ (sin(x) cos(x))² dx

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Which of the following integrals represents the area of the surface obtained by rotating the curve y = sin (x), 0<x <T/2, about the x-axis?
7/2
O A. 27
sin (x)/1+ (2 sin(x) cos(x))° dæ
п/2
о В. 2т
sin°(x)\/1+ (2 sin(z))° dx
7/2
O C. 27
sin°(x) /1+ (sin(æ) cos(x))° dæ
7/2
D. 2= /"zī 1 2 sin(2) cos(2) de
x/1+ 2 sin(x) cos(x) dx
O D.
п/2
zV1+ (2 sin(z) cos(æ))° dz
O E. 27
п/2
O F. 27
a/1+ (sin(æ) cos(x))² dæ
Transcribed Image Text:Which of the following integrals represents the area of the surface obtained by rotating the curve y = sin (x), 0<x <T/2, about the x-axis? 7/2 O A. 27 sin (x)/1+ (2 sin(x) cos(x))° dæ п/2 о В. 2т sin°(x)\/1+ (2 sin(z))° dx 7/2 O C. 27 sin°(x) /1+ (sin(æ) cos(x))° dæ 7/2 D. 2= /"zī 1 2 sin(2) cos(2) de x/1+ 2 sin(x) cos(x) dx O D. п/2 zV1+ (2 sin(z) cos(æ))° dz O E. 27 п/2 O F. 27 a/1+ (sin(æ) cos(x))² dæ
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