Which of the following mixtures would result in a buffer solution? Very briefly explain why for each one. i. 100 mL of 0.1M sodium acetate (NaOAc) + 50 mL of 0.1M hydrobromic acid (HBr). i. 50 mL of 0.01M acetic acid (HOAC) + 150 mL of 0.01M sodium hydroxide (NaOH). 100 mL of 0.02M sodium fluoride (NaF) + 50 mL of 0.02M potassium hydroxide (КОН). i.

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Chapter16: Acid-base Equilibria
Section: Chapter Questions
Problem 16.147QP
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Important Information
Atomic Masses (g/mol): H = 1.01, C = 12.01, N = 14.01, O = 16.00,
%D
Ne = 20.18, CI = 35.45, K = 39.10, Ar = 39.95,
Cu = 63.55, Ag = 107.87
%3D
%3D
wwm
Constants:
R = 8.314 J/mol·K = 0.08206 L·atm/mol·K
%3D
ww m
www m
F = 96,485 C/mol = 96,485 J/V•mol
%3D
Transcribed Image Text:Important Information Atomic Masses (g/mol): H = 1.01, C = 12.01, N = 14.01, O = 16.00, %D Ne = 20.18, CI = 35.45, K = 39.10, Ar = 39.95, Cu = 63.55, Ag = 107.87 %3D %3D wwm Constants: R = 8.314 J/mol·K = 0.08206 L·atm/mol·K %3D ww m www m F = 96,485 C/mol = 96,485 J/V•mol %3D
8. a) Which of the following mixtures would result in a buffer solution? Very briefly explain why
for each one.
100 mL of 0.1M sodium acetate (NaOAc) + 50 mL of 0.1M hydrobromic acid
(HBr).
i.
ii.
50 mL of 0.01M acetic acid (HOAC) + 150 mL of 0.01M sodium hydroxide (NaOH).
ii.
100 mL of 0.02M sodium fluoride (NaF) + 50 mL of 0.02M potassium hydroxide
(КОН).
Transcribed Image Text:8. a) Which of the following mixtures would result in a buffer solution? Very briefly explain why for each one. 100 mL of 0.1M sodium acetate (NaOAc) + 50 mL of 0.1M hydrobromic acid (HBr). i. ii. 50 mL of 0.01M acetic acid (HOAC) + 150 mL of 0.01M sodium hydroxide (NaOH). ii. 100 mL of 0.02M sodium fluoride (NaF) + 50 mL of 0.02M potassium hydroxide (КОН).
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