Which of the following sets of quantum numbers can be used to describe the 2 electrons in the He atom? For the possible sets, write the electron configuration and identify if it is a ground state or excited state configuration. i) n = 2, l = 0, ml = 0, ms = 1/2 and n = 1, l = 0, ml = 0, ms = 1/2 ii) n = 2, l = 0, ml = 0, ms = 1/2 and n = 2, l = 0, ml = 0, ms = 1/2 iii) n = 2, l = 1, ml = 0, ms = 1/2 and n = 2, l = 0, ml = 0, ms = 1/2 iv) n = 2, l = 0, ml = 0, ms =- 1/2 and n = 2, l = 0, ml = 0, ms = 1/2 v) n = 1, l = 0, ml = 0, ms = ½ and n = 1, l = 0, ml = 0, ms = -½
Which of the following sets of quantum numbers can be used to describe the 2 electrons in the He atom? For the possible sets, write the electron configuration and identify if it is a ground state or excited state configuration. i) n = 2, l = 0, ml = 0, ms = 1/2 and n = 1, l = 0, ml = 0, ms = 1/2 ii) n = 2, l = 0, ml = 0, ms = 1/2 and n = 2, l = 0, ml = 0, ms = 1/2 iii) n = 2, l = 1, ml = 0, ms = 1/2 and n = 2, l = 0, ml = 0, ms = 1/2 iv) n = 2, l = 0, ml = 0, ms =- 1/2 and n = 2, l = 0, ml = 0, ms = 1/2 v) n = 1, l = 0, ml = 0, ms = ½ and n = 1, l = 0, ml = 0, ms = -½
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter6: The Periodic Table And Atomic Structure
Section: Chapter Questions
Problem 6.96PAE: 6.96 When a helium atom absorbs light at 58.44 nm, an electron is promoted from the 1s orbital to a...
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Which of the following sets of quantum numbers can be used to describe the 2 electrons in the He atom? For the possible sets, write the electron configuration and identify if it is a ground state or excited state configuration.
i) n = 2, l = 0, ml = 0, ms = 1/2 and n = 1, l = 0, ml = 0, ms = 1/2
ii) n = 2, l = 0, ml = 0, ms = 1/2 and n = 2, l = 0, ml = 0, ms = 1/2
iii) n = 2, l = 1, ml = 0, ms = 1/2 and n = 2, l = 0, ml = 0, ms = 1/2
iv) n = 2, l = 0, ml = 0, ms =- 1/2 and n = 2, l = 0, ml = 0, ms = 1/2
v) n = 1, l = 0, ml = 0, ms = ½ and n = 1, l = 0, ml = 0, ms = -½
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