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- All of the following apply to Luria and Delbruck’s 1943 study of mutation rates in E. Coli and T1 phage except: A) it served as an example of an inflexible test B) it involved looking for T1-resistant bacteria as an end measure C) it showed that numbers of mutant organisms observed after T 1 phage were added to the culture tended to vary from experiment to experiment D) it rejected the possibility of adaptive mutations E) it supported the concept of spontaneous mutation ratesA microbial geneticist isolates a new mutation in E. coliand wishes to map its chromosomal location. She usesinterrupted-mating experiments with Hfr strains andgeneralized-transduction experiments with phage P1.Explain why each technique, by itself, is insufficient foraccurate mapping.Which of the following statements regarding transduction is FALSE? A) transduction reduces genetic variation within bacterial populations B) the inadvertent packaging of bacterial DNA into a phage particle can lead to generalized transduction C) specialized transduction can only be facilitated by a phage capable of integration into the bacterial genome D) generalized transduction involves the transfer of DNA that is exclusively bacterial E) specialized transduction must be preceded by viral integration and imperfect excision F) specialized transduction involves the transfer of both bacterial and viral DNA
- In 1944, Avery, Macleod, and McCarty provided strong evidence that DNA is the hereditary material in Streptococcus pneumoniae by Group of answer choices showing that avirulent cells could become virulent by the process of transduction none of these is true. showing that virulent cells could become avirulent if the DNA was destroyed after transformation showing that avirulent cells could not gain the ability to become virulent cells if conjugation was interrupted. showing that avirulent cells could not gain the ability to become virulent if DNA was destroyed after transformation.Austin Taylor and Edward Adelberg isolated some new strains of Hfr cells that they then used to map several genes in E. coli by using interrupted conjugation . In one experiment, they mixed cells of Hfr strain AB-312, which were xyl+ mtl+ mal+ met+ and sensitive to phage T6, with F− strain AB-531, which was xyl− mtl− mal− met− and resistant to phage T6. The cells were allowed to undergo conjugation. At regular intervals, the researchers removed a sample of cells and interrupted conjugation by killing the Hfr cells with phage T6. The F− cells, which were resistant to phage T6, survivedand were then tested for the presence of genes transferred from the Hfr strain. The results of this experiment are shown in the accompanying graph. On the basis of these data, give the order of the xyl, mtl, mal, and met genes on the bacterial chromosome and indicate the minimum distances between them.Austin Taylor and Edward Adelberg isolated some new strains of Hfr cells that they then used to map several genes in Escherichia coli by using interrupted conjugation. In one experiment, the researchers mixed cells of Hfr strain AB‑312, which were xyl+ mtl+ mal+ met+ and sensitive to phage T6, with F− strain AB‑531, which was xyl− mtl− mal− met− and resistant to phage T6. The cells were allowed to undergo conjugation. At regular intervals, the researchers removed a sample of cells and interrupted conjugation by killing the Hfr cells with phage T6. The F− cells, which were resistant to phage T6, survived and were then tested for the presence of genes transferred from the Hfr strain. The results of this experiment are shown in the graph. On the basis of these data, give the order of the xyl, mtl, mal, and met genes on the bacterial chromosome and the minimum distances between them in minutes. The origin of transfer is represented by the red triangle. The distances between genes are not…
- Does the Hershey and Chase experiment rule out the possibility that RNA is the genetic material of T2 phage? Explain. If it does not, redesign the experiments of Hershey and Chase to distinguish between DNA and RNA in the T2 phage.In the replica-plating experiments of the Lederbergs, bacterialcolonies appeared at the same locations on each of two secondaryplates becausea. T1 phage caused the mutations to happen.b. the mutations occurred on the master plate prior to T1 exposureand prior to replica plating.c. Both a and b are true.d. Neither a nor b is true.Generalized transduction can transfer: please explain the answer a.any DNA from the host genome b.only phage-specific DNA sequences c.genes flanked by insertion elements d.only genes near the site of integration
- The linear dsDNA genome of λ binds on the LamB receptor of E. Coli and conducts a normal lysogenic cycle. Exposure to stress will cause the excision of λ prophage from the E. Coli genome. The excised λ genome is then replicated, packaged, and released from the cell as mature λ phage particles and ready to infect other bacterial cells. Among λ phage particles,the transducing phage mediates a specific type of recombination. Understand this scenario and answer the following questions. 1. What are the basic requirements for the insertion of λ into the E. Coli genome? 2. What special features are found in the λ insertion site? 3. What type of recombination occurs with λ insertion in the E. Coli genome? 4. How you will differentiate λ transducing phage from normal λ phage? 5. What exclusive mechanism λ phage utilizes for recombination?In generalized transduction.... Choose from the answers below: random fragments of degraded bacterial DNA are packaged in phage particles. the maximum size of transduced DNA fragments is dependent on the size of the phage particles. the transducing DNA fragments are generated by faulty excision of a prophage from the host genome. a and b, but not c b and c, but not aA research group is studying a bacterium X that binds to mucosal cells in the lung and invades. Wildtype X has an LD50 value of 10 bacteria when administered to mice by inhalation. Using transposon mutagenesis, the researchers have isolated two mutants of X that they call Xmut1 and Xmut2, both of which have LD50 values of 105 when inhaled by mice. However, in tissue culture cells, Xmut1 can invade the cells just as well as wild-type X, while Xmut2 cannot. Provide a possible explanation for these results.