Which of the follwings are true? (There might be multiple correct answers) Compare and swap is a hardware based solution correct correct ]Basic Compare and swap ensures bounded waiting Test and set is a hardware solution that can be extended to a more complex alternative ]Implementing semaphore is more sophisticated than implementing test and set
Which of the follwings are true? (There might be multiple correct answers) Compare and swap is a hardware based solution correct correct ]Basic Compare and swap ensures bounded waiting Test and set is a hardware solution that can be extended to a more complex alternative ]Implementing semaphore is more sophisticated than implementing test and set
Computer Networking: A Top-Down Approach (7th Edition)
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Transcribed Image Text:Which of the follwings are true? (There might be multiple carrect answers)
Compare and swap is a hardware based solution correct correct
Basic Compare and swap ensures bounded waiting
|Test and set is a hardware solution that can be extended to a more complex alternative
|Implementing semaphore is more sophisticated than implementing test and set
Which of the follwings are true? (There might be multiple correct answers)
|In race condition multiple processes can execute shared information concurrently.
Process synchronization ensures data consistency.
Race condition does not create data inconsistency in a shared region.
Semaphore is only used to solve critical section problem.
![Suppose the 2 processes in peterson's solution are numbered 0 and 1. Which of the following is a
valid code statement in the entry section of process 1?
O flag[1] = false
O turn = 0
O flag[0] = false
turn = 1
# Define Flag[1]=TRUE;
# Define Flag[0]=FALSE;
# Define turn=1;
# We have 4 line of codes in critical section.
# Each line of the peterson solutions and critical section requires 2sec to execute.
Now if process 1 try to execute and enter in critical section after executing the entry section. what will
be the situation if context switch happens after 8sec?
O Process PO might enter in the critical section.
Process P1 will terminate and will not execute the reminder section.
O Contex switch can not take place after 8sec of execution.
Process PO never can enter the critical section.
Numerical Input
Suppose counting semaphore S is started from the value of 15. After that 10 times call the wait S operations and 10 times call the signal S. What is the
final value of S?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5faa7035-dfc3-479a-b113-31be2ca1585e%2F7b6da89a-41da-4c43-9b6d-a4e7ff451da0%2F6qj07ok_processed.png&w=3840&q=75)
Transcribed Image Text:Suppose the 2 processes in peterson's solution are numbered 0 and 1. Which of the following is a
valid code statement in the entry section of process 1?
O flag[1] = false
O turn = 0
O flag[0] = false
turn = 1
# Define Flag[1]=TRUE;
# Define Flag[0]=FALSE;
# Define turn=1;
# We have 4 line of codes in critical section.
# Each line of the peterson solutions and critical section requires 2sec to execute.
Now if process 1 try to execute and enter in critical section after executing the entry section. what will
be the situation if context switch happens after 8sec?
O Process PO might enter in the critical section.
Process P1 will terminate and will not execute the reminder section.
O Contex switch can not take place after 8sec of execution.
Process PO never can enter the critical section.
Numerical Input
Suppose counting semaphore S is started from the value of 15. After that 10 times call the wait S operations and 10 times call the signal S. What is the
final value of S?
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