Which of the choices best describes the above code?Group of answer choicesch occupies one byte, j occupies 2 bytes and they are both local variablesch occupies one byte, j occupies 2 bytes and they are both global variablesch occupies two bytes, j occupies 1 byte and they are both global variablesch and j are both constants main. BLOCK 1. BLOCK 20000120006BR;global variable #1c¡global variable #2d000300ch:0004 0000j:0006 DIFC15 main:;scanf("%c %d", &ch, &j)charIn,dch,dj,dj,d5,ij,dch,d1,ich,dch,dcharOut,d'\n',icharout,dj,d\n',icharout,dLDBA0009 F10003STBA000c 310004DECI000F C10004LDWA¡j += 50012 600005ADDA0015 E10004STWA0018001BD10003LDBA;ch++600001ADDA001E F10003STBA0021 D10003LDBA¡printf("%c\n%d\n", ch, j)0024 F1FC16STBA0027 DO000ALDBA002A F1FC16STBA002D 390004DECO0030 DO000ALDBA0033 F1FC16STBA0036 00STOP0037.END

In the given assembly code, two global variables are used. The first variable name is "ch" of type…

Group of answer choices ch occupies one byte, j occupies 2 bytes and they are both local variables ch occupies one byte, j occupies 2 bytes and they are both global variables ch occupies two bytes, j occupies 1 byte and they are both global variables ch and j are both constants

Group of answer choices ch occupies one byte, j occupies 2 bytes and they are both local variables ch occupies one byte, j occupies 2 bytes and they are both global variables ch occupies two bytes, j occupies 1 byte and they are both global variables ch and j are both constants

Programming with Microsoft Visual Basic 2017

8th Edition

ISBN:9781337102124

Author:Diane Zak

Publisher:Diane Zak

Chapter6: Sub And Function Procedures

Section: Chapter Questions

Problem 12RQ

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Question

Which of the choices best describes the above code?

Group of answer choices

ch occupies one byte, j occupies 2 bytes and they are both local variables

ch occupies one byte, j occupies 2 bytes and they are both global variables

ch occupies two bytes, j occupies 1 byte and they are both global variables

ch and j are both constants

main
. BLOCK 1
. BLOCK 2
0000
120006
BR
;global variable #1c
¡global variable #2d
0003
00
ch:
0004 0000
j:
0006 DIFC15 main:
;scanf("%c %d", &ch, &j)
charIn,d
ch,d
j,d
j,d
5,i
j,d
ch,d
1,i
ch,d
ch,d
charOut,d
'\n',i
charout,d
j,d
\n',i
charout,d
LDBA
0009 F10003
STBA
000c 310004
DECI
000F C10004
LDWA
¡j += 5
0012 600005
ADDA
0015 E10004
STWA
0018
001B
D10003
LDBA
;ch++
600001
ADDA
001E F10003
STBA
0021 D10003
LDBA
¡printf("%c\n%d\n", ch, j)
0024 F1FC16
STBA
0027 DO000A
LDBA
002A F1FC16
STBA
002D 390004
DECO
0030 DO000A
LDBA
0033 F1FC16
STBA
0036 00
STOP
0037
.END

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