which of these comparison between an ANOVA and t test is correct?  A. a t test provides more flexibilty in research studies than an ANOVA  B. An ANOVA examines wheater mean differences exists between conditions wheres t test does not  C. An ANOVA can be used to compare three or more conditions wheres a t test cannot D. A t test can be used to compare two conditions wheres an ANOVA cannot.

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A:

Q: in a random sample of 400 Students 332 stated that there is were nonsmokers. Based on tr Sample,…

A: Given,n=400x=332p^=xnp^=332400=0.8301-p^=1-0.830=0.170α=1-0.90=0.1α2=0.05Z0.05=1.645     (from…

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A:

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A: Given that  Sample size n =24 Sample mean =30150 Sample Standard deviation =10560 NOTE:- According…

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A: Given that μ=32,σ=4 Using Emperical rule Find P ( 28<X<36) = ? P ( 24<X<32) = ?

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A: Given that.   X~N( 0 , 1 )   μ=0  , ?=1 (for standard normal distribution)    Z-score =( x - μ )/?

Q: 1 1/6 2 3 4 5 6 1/6 1/6 1/6 1/6 1/6 e expected value of X + Y - E(X+Y) and the -iance of X+Y-…

A: Solution

Q: What is the medium of these figure skating ratings? 5.0,6.0, 7.0, 7.5, 8.0, 9.0, 10.0?

A: The given data is already arranged in ascending order.5.0 , 6.0, 7.0, 7.5, 8.0, 9.0, 10.0

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A: Given data: n = 1001 X = 530

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A: Given that

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Q: Which of the following Pearson correlations shows the greatest strength or consistency of…

A: Solution Given Pearson correlations shows the greatest strength or consistency of relationship?

Q: QUESTION 7 If P(A) = 0.2, P(BIA) = 0.45, P(AUB) = 0.60, then compute P(B) with 3 decimals.

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A: The z score is 0.8.

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A: Solution: Total  students = 85 One student is randomly selected.

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Q: 3. find the posterior distribution for 0, i.e. k(0|x)

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Q: Question 6 Assume that the readings at freezing on a bundle of thermometers are normally…

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Q: QUESTION 2 A normal probability distribution   a. is a continuous probability distribution.   b.…

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Q: Assume that the readings at freezing on a bundle of thermometers are normally distributed with a…

A: Here, µ= 0 , σ= 1. Here, Z follows a normal distribution.

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Q: ver engin

A: Objective Function: Maximize Z = 0.60 S + 0.50 H  S – Sausage Biscuit  H – Ham Biscuit Constraints:…

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A: Given as,

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Q: Using the TI-84 Plus calculator, find the area under the standard normal curve that lies between the…

A: Are under normal curve has calculated using TI-84 Plus calculator.

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Q: Post hoc test such as scheffe and turkeys HSD, are never necessary for an analysis of variance…

A: Solution Turkeys HSD are used in the analysis of ANOVA.