Which of these is a possible solution for tanxcosx=0 in the interval xE [0, 2?]?   A. x = ?/2 B. x = ?/4 C. x = ?/3 D. x = 0

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A: Answer is 0  Explanation is given below..

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Q: -When the (4tan e. tan2 0 = 1),the value of (0) from 0° to 360°.

A: We will use the formula tan2θ = 2 tanθ1-tan2θ Hence 4tanθ . tan2θ = 14 tanθ2 tanθ1-tan2θ = 18…

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A: This is a basic trignometry problem

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A: Topic:- trigonometry

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A: tan2ydy=sin3xdxIntegrate both sides and solve.

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A: We have to find the value sin(x)

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A: As per our guidelines we are supposed to answer only one question

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A: See the attachment

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A: Here we find the correct option.

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A: given function : y=sin∅ -1≤sin∅≤1 so minimum value of function is -1

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Q: Solve f'(x) = 0 for x, 0<or equal to x< or equal to 2 pie, wher f(x) = x+2 cosx

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Q: 1. Given 0<0 < 27, solve tan 0 = 0. %3D )号,警 O 0, 7 O O

A: In this question we have to find the value of x at which tan x =0

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A: Differentiation: y=tanx+3cscxdydx=sec2x-3cscx .cotxy=sinx+secx-4ln xdydx=cos x-secx tanx-4x

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Q: Which of the following statements is true? @ Soue(x*) dr= - coa(x) +c x²+2 - dx =x+ tan(x) +C x²+1…

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Q: 5. Given 0 < 0 < 27, solve tan 0 = 0. 2 2 O 0,

A: Given:           0≤θ≤2π , tan(θ)=0

Q: (6) In the interval 0 <x< 2n, the solutions of the equation tan? (x) = tan(x) are? (A) "/4 (B) "/4,…

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