Question 5: The sp, orbitals are separated by by and are 1. 109 degrees, 120 degrees, planer. 2. 120 degrees, 109 degrees, planer. 3. 180 degrees, 109 degrees, tetrahedral. 4. 120 degrees, 109 degrees, tetrahedral. 5. 180 degrees, 90 degrees, octahedral. _while the sp, orbitals are separated Question 6: Which of the following compounds has a chiral center? 1. CH4 2. Ch3CI 3. Ch2C12 4. CHCIFI

Question 5: The sp, orbitals are separated by by and are 1. 109 degrees, 120 degrees, planer. 2. 120 degrees, 109 degrees, planer. 3. 180 degrees, 109 degrees, tetrahedral. 4. 120 degrees, 109 degrees, tetrahedral. 5. 180 degrees, 90 degrees, octahedral. _while the sp, orbitals are separated Question 6: Which of the following compounds has a chiral center? 1. CH4 2. Ch3CI 3. Ch2C12 4. CHCIFI

Chemistry

9th Edition

ISBN:9781133611097

Author:Steven S. Zumdahl

Publisher:Steven S. Zumdahl

Chapter9: Covalent Bonding: Orbitals

Section: Chapter Questions

Problem 77AE: What type of molecular orbital would result from the in-phase combination of the two dxz atomic...

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What type of molecular orbital would result from the in-phase combination of the two dxz atomic orbitals shown below? Assume the x-axis is the internuclear axis.
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There are two compounds of the formula Pt1NH322Cl2:The compound on the right is called cisplatin, and the compoundon the left is called transplatin. (a) Which compoundhas a nonzero dipole moment? (b) One of these compoundsis an anticancer drug, and one is inactive. The anticancerdrug works by its chloride ions undergoing a substitutionreaction with nitrogen atoms in DNA that are close together,forming a N—Pt—N angle of about 90°. Which compoundwould you predict to be the anticancer drug?
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when a molecule is said to be chiral or asymmetric?
Your chemistry professor draws a number of molecules on the board: (1) CH4 ; (2) H2C=CH2 ; (3) H2C=C=CH2 ; and (4) H2C=C=C=CH2. You muse about all the molecules that chemists draw on a two-dimensional board and wonder which ones are actually planar, existing basically as they appear on the board, and which ones are not plane but rather three-dimensional. Answer ALL of the following questions. What are the specific orbital overlaps (i.e., sp3-sp3) that are in each of the molecules? What are the bond angles for each central atom in each molecule? Which molecules are planar and which are non-planar?
Any tetrahedral atom with four different groups attachedcan be a chiral center. Which of these species is optically active?(a) CHClBrF(b) NBrCl₂H⁺(c) PFClBrI⁺(d) SeFClBrH
all of the orbital overlaps in NCO ‒---- Which of the following statements is TRUE? Select one: Pi bonds are stronger than sigma bonds. The sp2 hybridization scheme for carbon allows for the formation of two pi bonds. A carbon-carbon triple bond consists of one π bond. Pi bonds can hold 4 electrons: 2 above the bond axis, and 2 below the bond axis. A molecule with the VSEPR class AX4E2 will have a central atom that is sp3d2 hybridized.
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