Why did he take the average this way? He could just add all the numbers to each other than multiplies by their count. And when I did it I got a different answer. (10+15+13+9+32+10+25+0)/8= 6982.5. I would really appreciate an explanation. AM13cm10cm 25cm32cm9cm7 x 70cm10cm 15cmthe scale is 1: 7,5001CM on the map=7500 CM in arears1CM=75CMStep 2/4(i) Average height rule:Take average height of two sides for each area10+15h₂h3h₁h5h6h7=215+13213+929+32232+10210+25225+02= 12.5cm= 14cm11cm20.5cm= 21cm= 17.5cm12.5cmthereforetotal area incm² =h₁ × 10 + h₂ × 10 + h3 × 10 + h4 × 10 + h5 × 10 + h6 × 10 + h7 × 10area= 12.5 x 70+ 14 x 70 + 11 × 70 + 20.5 x 70 + 21 x 70+ 17.5 × 70+ 12.5 × 70area= 7,630cm²

Why did he take the average this way? He could just add all the numbers to each other than multiplies by their count. And when I did it I got a different answer. (10+15+13+9+32+10+25+0)/8= 6982.5. I would really appreciate an explanation.

Why did he take the average this way? He could just add all the numbers to each other than multiplies by their count. And when I did it I got a different answer. (10+15+13+9+32+10+25+0)/8= 6982.5. I would really appreciate an explanation.

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter2: Equations And Inequalities

Section2.7: More On Inequalities

Problem 44E

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Question

AM
13cm
10cm 25cm
32cm
9cm
7 x 70cm
10cm 15cm
the scale is 1: 7,500
1CM on the map=7500 CM in arears
1CM=75CM
Step 2/4
(i) Average height rule:
Take average height of two sides for each area
10+15
h₂
h3
h₁
h5
h6
h7
=
2
15+13
2
13+9
2
9+32
2
32+10
2
10+25
2
25+0
2
= 12.5cm
= 14cm
11cm
20.5cm
= 21cm
= 17.5cm
12.5cm
therefore
total area in
cm² =
h₁ × 10 + h₂ × 10 + h3 × 10 + h4 × 10 + h5 × 10 + h6 × 10 + h7 × 10
area
= 12.5 x 70+ 14 x 70 + 11 × 70 + 20.5 x 70 + 21 x 70+ 17.5 × 70+ 12.5 × 70
area= 7,630cm²

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