Why does our node class have two versions of the link member function? One is public, the other is private. One is to use with a const pointer, the other with a regular pointer. One returns the forward link, the other returns the backward link. One returns the data, the other returns a pointer to the next node.
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A: a) Total=(queueRear-queueFront)+1 =(60-35)+1 =25+1 =26
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- q16) In the linked list, last node address field is stored with ________ value. a. Depends on the problem b. Undefined c. Pointing to new node. d. NULLShow what is produced by the following C++ code. Assume the node is in the usual info-link form with the info of the type int. (first, temp, and p are pointers of type nodeType.) first = new nodeType;first->info = 78;p = new nodeType;p->info = 26;first->link = p;p->link = nullptr;temp = new nodeType;temp->info = 39;temp->link = first;p = first;first = temp;temp = p->link;cout << first->info << " " << temp->info << " "<< p->info << endl;IN C LANGUAGE When inserting a node into a linked list, where (in memory) will that node be placed if there is no overflow? A) The location of the AVAIL pointer B) The next contiguous spot of memory from the last node C) The very end of the contiguous memory block D) A randomized memory location
- The linked list is إختر أحد الخيارات: a. Array of nodes structure b. array of pointers each one point to node structure c. A link that points to another link d. a pointer that points to node structure أخلِ اختياريConsider the following struct declaration that defines a node of a linked link. struct Node{ char ch; struct Node* link; }; Consider the linked list in Figure 1. Suppose head and temp are Node type pointers. The head node of the linked list is pointed by the head pointer. Each node stores one character type data as shown in Figure 1. What will be the output of the following pseudocode? foo(head) 1.if head is NULL a. return 2. temp = head 3. foo(temp->link) 4. print temp->chWhich node contains a pointer to its parent?a) root nodeb) right most childc) left most childd) left sibling
- 1:If the single linked list is non-empty, what is the stored in the link field of the last node?Which link types of link list do not require a pointer to point at the starting element and still be able to access all the elements by traversing for C++?Implement the function below void swap(int pos1, int pos2) {} For LinkedList, to maintain integrity of data in the structure, you are not to swap directly the element, nor remove a node. Instead, you are to only change the nodes' next pointers. Inital code to be completed: class LinkedList : public List { node* head; node* tail; int index; node* create_node(int num) { node* n = (node*) malloc(sizeof(node)); n->element = num; n->next = NULL; return n; } public: LinkedList() { index = 0; head = NULL; tail = NULL; } int add(int num) { addTail(num); return index; } int get(int pos) { node* currnode = head; int count =0; while (currnode != NULL){ count++; if (count == pos){ return currnode -> element; }else{ currnode = currnode -> next; } }…
- int F(node<int>&p){int c=0; while(p!=0){p=p->next; c++; } return c;} This function is a. return the number of items in the linked list b. return the number of items in a linked list and destroy the linked list c. None of these d. destroy the list and free all allocated nodesIn a singly linked list the link field of —- contains a null pointer. A) first node B) any node C) middle node D) the last nodeWrite a function named “removeNode” that takes a head of the linked list of struct Student and a student name (String). The function removes the node that has the student name. Assume the following declaration and how the function is called: struct Student { String name; int score; Student *next; }; void removeNode (Student *firstStudent, String studentName); int main() { Student *firstStudent; // address of the head // Assuming some code to fill in all data // Student *newStudent = new Student; // fill in data for newStudent insertNode(firstStudent, newStudent); return 0; }