Please type your Solutions so that they are easy to read I have bad eyesight NArmatureForceISdownFSBrushesVoltage sourceFIGURE 20-37 Diagram of a simplede motor. (Magnetic field lines areas shown in Fig. 20-36.)22 V(a)FIGURE 20-11 (a) Force on acurrent-carrying wire placed in amagnetic field B; (b) same, butcurrent reversed; (c) right-hand rulefor setup in (b), with current Ishown as if a vector with direction.Force is up(b)22 VINDUSTRIALB(c) Right-hand rule Why forces are generated for parts of the loop (actually rectangle in Fig 20-37) and not for otherparts of the loop. Refer back to Fig 20-11 and the Force equation with sin theta (max forcewhen theta is 90 degrees or perpendicular to magnetic field lines.)your experience applying the Right-Hand Rule to explain up and down forces acting together togenerate clockwise motion of the armature

Answered: Image /qna-images/answer/f1269a3f-3423-4932-a649-66b43445d4c3.jpg

Why forces are generated for parts of the loop (actually rectangle in Fig 20-37) and not for other parts of the loop. Refer back to Fig 20-11 and the Force equation with sin theta (max force when theta is 90 degrees or perpendicular to magnetic field lines.) your experience applying the Right-Hand Rule to explain up and down forces acting together to generate clockwise motion of the armature

Why forces are generated for parts of the loop (actually rectangle in Fig 20-37) and not for other parts of the loop. Refer back to Fig 20-11 and the Force equation with sin theta (max force when theta is 90 degrees or perpendicular to magnetic field lines.) your experience applying the Right-Hand Rule to explain up and down forces acting together to generate clockwise motion of the armature

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter19: Magnetism

Section19.5: Magnetic Force On A Current -Carrying Conductor

Problem 19.3QQ: As a charged particle moves freely in a circular path in the presence of a constant magnetic field...

See similar textbooks

Similar questions

Find the magnitude and direction of the magnetic field at the point equidistant from the wires in Figure 22.58(a), using the rules of vector addition to sum the contributions from each wire.
A 5.0-m section of a long, straight wire carries a current of 10 A while in a uniform magnetic field of magnitude 8.0103T . Calculate the magnitude of the force on the section if the angle between the field and the direction of the current is (a) 45°; (b) 90°; (C) 0°; or (d) 180°.
Determine the magnetic field on the central axis at the opening of a semi-infinite solenoid. (That is, take the opening to be at x = 0 and the other end to be at x= .)
How is the percentage change in the strength of the magnetic field across the face of the toroid related to the percentage change in the radial distance from the axis of the toroid?
Is the work required to accelerate a rod from rest to a speed v in a magnetic field greater than the final kinetic energy of the rod? Why?
As a charged particle moves freely in a circular path in the presence of a constant magnetic field applied perpendicular to the particles velocity, the particles kinetic energy (a) remains constant, (b) increases, or (c) decreases.
A charged particle moves in a straight line through a region of space. Which of the following answers must be true? (Assume any other fields are negligible.) The magnetic field (a) has a magnitude of zero (b) has a zero component perpendicular to the particles velocity (c) hits a zero component parallel to the particles velocity in that region.
A circular loop of wire is held in a uniform magnetic field, with the plane of the loop perpendicular to the field lines. Which of the following will not cause a current to be induced in the loop? (a) crushing the loop (b) rotating the loop about an axis perpendicular to the field lines (c) keeping the orientation of the loop fixed and moving it along the field lines (d) pulling the loop out of the field