7. At 25 °C, 0.0010 M NH4OH has a conductivity of 3.40 x 10-³ Sm¹¹. Given (inSm²mol-¹): A, (NH4C1) = 0.0147, A. (NaOH) = 0.02481, A, (NaCl) = 0.01265,Calculate Kb.

In this we would use dissociation equation of NH4OH to calculate Kb.

Answered: 7. At 25 °C, 0.0010 M NH4OH has a…

7. At 25 °C, 0.0010 M NH4OH has a conductivity of 3.40 x 10-³ Sm¹¹. Given (in Sm²mol-¹): A, (NH4CI) = 0.0147, A. (NaOH) = 0.02481, A, (NaCl) = 0.01265, Calculate K.

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter10: Effect Of Electrolytes On Chemical Equilibria

Section: Chapter Questions

Problem 10.4QAP

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Concept explainers

Potentiometric Titrations

Potentiometric titration is one of the important titration methods and is mainly carried out to characterize acid solutions. It follows a method similar to that of the normal titration technique, but the main difference is that there is no indicator used in the potentiometric titrations. Instead of using an indicator, electrodes are employed for monitoring the whole titration process. A scientist named Robert Behrend did the potentiometric titration for the first time, and it was done using the mercurous solution and potassium chloride.

Question

7. At 25 °C, 0.0010 M NH4OH has a conductivity of 3.40 x 10-³ Sm¹¹. Given (in
Sm²mol-¹): A, (NH4C1) = 0.0147, A. (NaOH) = 0.02481, A, (NaCl) = 0.01265,
Calculate Kb.

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Why the concnetration with mol/dm^3 was used in kb calculations with no conversion to mol/m^3 to have a coherent units?

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Thank you, but why you used the 0.0010 M (mol/dm^3) when calculating the Kb without converting it to mol/m^3 so we can have a coherent units?

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