program for our LAB emulator which proves that 234 is even number
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- In MIPS assembly, implement integer division using rounding (rather than truncation). This is accomplished by taking the remainder of the division and dividing it by the original divisor. If the new quotient is higher than or equal to one, multiply it by one.Otherwise, leave the original quotient alone.In MIPS assembly, implement integer division using rounding (rather than truncation). This is accomplished by taking the remainder of the division and dividing it by the original divisor. If the new quotient is higher than or equal to one, multiply it by one.Otherwise, leave the original quotient alone.In MIPS assembly, implement integer division using rounding (rather than truncation). This is accomplished by taking the remainder of the division and dividing it by the original divisor. If the new quotient is higher than or equal to one, multiply it by one.Otherwise, leave the original quotient alone.In MIPS assembly, implement integer division using rounding (rather than truncation).…Challenge: Use MIPS(MARS) to create a program that takes an 8-bit binary number and returns it as a binary-coded decimal (BCD).Using MIPS in assembly language, you are to create a MIPS program that demonstrates that the associative law fails in addition for floating point numbers (single or double precision). You only need to demonstrate it for single precision. Remember the associative law is a + (b + c) = (a + b) + c. *Also have a lot of comments in your program as this is an assembly language program. Make the code neat and readable.
- Write a program in MIPS assembly that allows replacing a substring with another substring. Use any function and variable of your choice. For example: Input: - Initial text: XXabXXcd - Word to replace : XX - Replacement word: YY Output: YYabYYcdWrite a MIPS program that will handle calculating minifloat addition for two numbers using the rules discussed in class and storing each of the parts as a binary integer. To do this, each ‘minifloat’ number will need to be represented (I suggest hard coded) as one register for the sign, one for the exponent part, one for the ‘significand’ (which you then convert to the fraction part). Hard coding means here that you don’t need to read in the 6 parts as user input, just have something like li $s0, 0 li $s1, 12 li $s2, 5 which is equivalent to a minifloat of 0 1101 101 = 1.101 * 2^(12-7) = 1.101*2^5 This means your program will be work with at least 6 registers as variables. For testing, show that your program can correctly calculate the Lab 5 X+Y and A+B and then one other example of your choosing. Don’t worry about special cases of 0 0000 000 or 1 1111 111 or similar, but your program should detect overflow. This will involve a lot of (in your head) jumping back and forth between…Can someone please write out the code for a Mips program that calculates the nth root of any number? I did get the formula from someone here, which I am so grateful for, but I still do not understand how to get it into working code. I am new at trying to learn this and I'm doing it by myself so there is so much to know, so I sort of need it spelled out for this one. Thanks much!
- Hello. Please answer the attached RISC-V question correctly by converting the given C code to RISC-V. There is already some RISC-V code written, and you have to complete the rest of it based on the given C code. The code must be recursive and have comments that show what's happening. *If you correctly convert the code and make sure that it is recursive and has comments, I will give you a thumbs up. Thank you.I'm having trouble fixing this error in my Mathematica 12.0 code, I'm trying to make a dynamic clock but whatever I do to implement the hour minute and second hands it keeps giving me this error, any help is greatly appriciated.Using MIPS in assembly language, you are to create a MIPS program that demonstrates that the associative law fails in addition for floating point numbers (single or double precision). You only need to demonstrate it for single precision. Remember the associative law is a + (b + c) = (a + b) + c. *Include a screenshot of the code running, Also have a lot of comments in your program as this is an assembly language program. Make the code neat and readable.