
In MIPS assembly, implement integer division using rounding (rather than truncation). This is accomplished by taking the remainder of the division and dividing it by the original divisor. If the new quotient is higher than or equal to one, multiply it by one.
Otherwise, leave the original quotient alone.In MIPS assembly, implement integer division using rounding (rather than truncation). This is accomplished by taking the remainder of the division and dividing it by the original divisor. If the new quotient is higher than or equal to one, multiply it by one.
Otherwise, leave the original quotient alone.In MIPS assembly, implement integer division using rounding (rather than truncation). This is accomplished by taking the remainder of the division and dividing it by the original divisor. If the new quotient is higher than or equal to one, multiply it by one.
Otherwise, leave the original quotient alone.In MIPS assembly, implement integer division using rounding (rather than truncation). This is accomplished by taking the remainder of the division and dividing it by the original divisor. If the new quotient is higher than or equal to one, multiply it by one.
Otherwise, leave the original quotient alone.

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- For a positive integer n, what is the value of the counter after the following code has been executed. (Both C and Python code are included, use the language you are familiar with.) C code: int i,j,k, counter; python code: counter = 0 counter = 0; for ( i=1; i<=n; i++ ) for ( j=1; j<=i; j++) for ( k=1; k<=j; k++ ) for i in range (1, n+1) : for j in range (1,i+1) : for k in range (1, j+1) : counter = counter + 1 counter ++;arrow_forwardProgramming Project: For Loops Write an Assembly Language Program that produces the Times Table for a specific integer value between 1 to 12. NOTE: You choose and hard code only one value (i.e. 7) and produce the times table for that value. Also note that since you are using registers and memory locations make sure that at each step you screen shot each result for each part of the Times Table. For example 7 x 12 = 84 but in Hexadecimal the value is 54. Sample code in C #include void main() ( int i, j; printf("Enter an integer: "); scanf("%d", &i); printf("Times %d Table\n", i). for(j = 0; j<= 12; j =j+1) { printf("%d x %d = %d\n", j, 1. j'i); } printf("\n");arrow_forwardIm having trouble with this problem in writing a masm code for assembly language.arrow_forward
- There are three single precision floating point numbers, numA, numB and numC. Write a piece of code in MIPS assembly language that compares two numbers numA and numb, if numB is greater than numA, add them and save the result in numC. Otherwise save 0 in numC.arrow_forwardPlease show the output of the following code in assembly:arrow_forwardExplain briefly how the weighted approach may be used to convert decimal to ternary in a ternary environment.arrow_forward
- please give a step by step implementation of this using only operators in the nand2tetris hack assembly languagearrow_forwardIn C, both long x and int *y are 8-byte values. How can we can tell which one is which in the assembly compiled from the C? (l.e., what is true of one but not the other? If several answers seem correct, pick the most precise option.) A. x is stored in a register, y in memory B. x is modified using addq, y using addl C. x may be an argument to add but y won't be D. When an argument of mov, a register storing x will never be inside parentheses E. When an argument of mov, a register storing y will always be inside parenthesesarrow_forwardwrite in assebly language using lc3 simulator LC3 simulator-https://wchargin.com/lc3web/ Write a program that implements a for loop that adds 5 to R3 every iteration a. Increment a register by 1 in every cycle of the loop to keep track of the loop iterationsb. Store the maximum amount of iterations that the loop can have in a memory locationc. Your for loop should start at 0 iterations (i.e. i = 0) and stop looping once the maximum is reached Psuedo code: .ORIG x3000 ; Step 1: Clear R3 ; Step 2: Clear R0 ; Step 3: Load the value of MAX into R1 (maximum amount of iterations) ; Step 4: Take the two's compliment of R1 (2 instructions!) loop ; Step 5: Add #5 to R3 (result) ; Step 6: Increment R0 (loop iteration counter) ; Step 7: Add R1 and R0 and put the result in R2 (Since we did a 2's complement on R1, we are essentially subtracting R1 from R0) ; Step 8: Branch if negative back to loop (this means that R1 > R0 and we need to keep looping) ; Step 9: Halt CPU…arrow_forward
- Thank you, but I'm just not able to follow what is being done. It looks to me like the first minterm was left out of the initial step with no explanation as to why, and then it says MXY' + M'XY + MXY = (MX + M' + M)XY', but if I multiply out (MX + M' + M)XY', I get MXY'+M'XY'+MXY'. The M'XY' is not in the left side; so I don't see how this works. Then, later on, a complement law is mentioned, which does not exist in the chart, and there is no law/identity in the chart that matches going from XY' to X'+Y'. I apologize for being dumb here, but I'm just not following how you're getting from one expression to another. Could you please dumb it down even more for me. Thank you.arrow_forwardConsider the code presented below: y = (1, 9, 2) y[1]=8 print(y) What do we get when we execute this code? Answer:arrow_forwardProb 7. We have learned in the class that using the barrel shifter, we can implement multiplication/division of a number for some special cases with addition, subtraction, and reversed subtraction instructions as well as shift instructions. For each of the following calculations, write a single-line assembly code to perform it using this approach assuming signed integers A and B are saved in r0 and ri respectively: (a) A = 7 * B / 8 (b) A 7 B/8 5arrow_forward
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