Write a program that outputs prime numbers. This program should work as follows:
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- In Java Integer in is read from input. Write a while loop that iterates until in is less than or equal to 0. In each iteration: Update in with the quotient of in and 7. Output the updated in, followed by a newline. Click here for exampleEx: If the input is 2401, then the output is: 343 49 7 1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 import java.util.Scanner; public class QuotientCalculator { publicstaticvoidmain(String[] args) { Scannerscnr=newScanner(System.in); intin; in=scnr.nextInt(); /your code here/ } }Knowing that (x + 1)2 = x2 + 2x + 1,and that multiplication is more time consuming than addition, write an efficientprogram that displays the first ten natural numbers and their squares. Knowingthat (x + 1)3 = x3 + 3x2 + 3x + 1, the same process can be followed to displaythe cubes of these numbers.Here is a sample run: 0^2 = 01^2 = 12^2 = 4...8^2 = 649^2 = 8110^2 = 100explain the output of this program #include <stdio.h>#include <unistd.h> int main(){ int i; printf("before fork, my pid is %d\n" , getpid()); for (i=0; i<3; i++){ if ( fork()== 0 ) printf("Hi, I am child. My pid is %d\n", getpid()); }}
- JAVA PROGRAM Modify this program with further modifications as follows: The test case must pass when uploaded to Hypergrade. import java.io.*;import java.util.*;public class Main{ public static void main(String[] args) { List<String> girlsNames = loadNames("Girlnames.txt"); List<String> boysNames = loadNames("Boynames.txt"); if (girlsNames == null && boysNames == null) { System.out.println("Both files are missing. Exiting..."); return; } else if (girlsNames == null) { System.out.println("Girlnames.txt is missing. Exiting..."); return; } else if (boysNames == null) { System.out.println("Boynames.txt is missing. Exiting..."); return; } Scanner scanner = new Scanner(System.in); while (true) { System.out.print("Enter a name (or 'QUIT' to exit): "); String input = scanner.nextLine(); if…Write a Python program in a Linux/UNIX script called myprogram.py. Write a Python program that continuously (i.e., in an infinite loop) asks the user for a number m. At each iteration of the loop, check in parallel whether m is greater than 10, greater than 20, and greater than 30. Make sure that the three comparisons may be performed in parallel (i.e., so that the three outputs can theoretically be printed in any order). Use the smallest number of processes. Make sure you don’t create zombie processes. Use the code below as a template. Use this template: from os import wait,waitpid,fork # write your code here while (True): #make sure to indent this and the next lines m=float(input('Give me a number: ')) # your code hereImplement a subprogram which takes 4 numbers in the argument registers $a0...$a3, andreturns the largest value and the average in $v0 and $v1 to the calling program. Theprogram must be structured as follows:Subprogram largestAndAverage($a1, $a2, $a3, $a4){ int var0 = $a0, var1 = $a1, var2 = $a2, var3 = $a3; $s0 = getLarger($a1, $a2); $s0 = getLarger($s0, $a3); $v0 = getLarager(s0, $a4); // Largest is in $v0 $v1 = (var0 + var1 + var2 + var3)/ 4; // Aversge is in $v1 return;}Subprogram getLarger($a0, $a1) { $v0 = $a0 if ($a1 > $a0) $v0 = $a1 return;}Note the use of the variables var0...var3. Because the values of $a0 and $a1 (at least) arechanged on the call to getLarger, they will not be available when they are needed to calculatethe average, and must be stored on the stack. To do this problem correctly, you mustcalculate the maximum value using the getLarger subprogram shown here, and it must becalled before the average is calculated. This implies that at a minimum $a0 and $a1 must…
- Implement a subprogram which takes 4 numbers in the argument registers $a0...$a3, andreturns the largest value and the average in $v0 and $v1 to the calling program. Theprogram must be structured as follows:Subprogram largestAndAverage($a1, $a2, $a3, $a4){ int var0 = $a0, var1 = $a1, var2 = $a2, var3 = $a3; $s0 = getLarger($a1, $a2); $s0 = getLarger($s0, $a3); $v0 = getLarager(s0, $a4); // Largest is in $v0 $v1 = (var0 + var1 + var2 + var3)/ 4; // Aversge is in $v1 return;}Subprogram getLarger($a0, $a1) { $v0 = $a0 if ($a1 > $a0) $v0 = $a1 return;}Take note of how var0...var3 are used. The values of $a0 and $a1 (at least) must be placed on the stack because they are not immediately available when needed to calculate the average because they are modified during the call to getLarger. You must use the getLarger subprogram displayed above to calculate the greatest value for this problem, and it must be called before the average calculation. This indicates that at the very least $a0…4) Read the following second main class. Guess its output. class Test { public static void main(String s[]) throws Exception { TextThread x = new TextThread ("Hello"); TextThread y = new TextThread ("Java"); x.start(); x.join(); y.start(); System.out.println("I am Main thread"); } }modify hello.c to print out Hello, world! four times. One restriction is that you only can use fork(), wait(), and exit() in your code. You cannot add/modify the printf() statement nor adding any type of loops to your code. Modify this file to print out Hello, world! x4 timesHint: think about how many processes you needand come up with the right number of fork()*/ /*hello.c */#include <sys/types.h>#include <errno.h>#include <stdio.h>#include <sys/wait.h>#include <stdlib.h>#include <string.h>#include <unistd.h> int main(){ printf("Hello, world!\n"); return 0;}
- Java Program ASAP Modify this program so it passes the test cases in Hypergrade becauses it says 5 out of 7 passed. Also I need one one program and please correct and change the program so that the numbers are in the correct places as shown in the correct test case. import java.io.BufferedReader;import java.io.FileReader;import java.io.IOException;import java.util.ArrayList;import java.util.Arrays;import java.util.InputMismatchException;import java.util.Scanner;public class FileSorting { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); while (true) { System.out.println("Please enter the file name or type QUIT to exit:"); String fileName = scanner.nextLine(); if (fileName.equalsIgnoreCase("QUIT")) { break; } try { ArrayList<String> lines = readFile(fileName); if (lines.isEmpty()) { System.out.println("File " +…Use a Bootstrap class to center the following text: <p class="">Hello World!</p>Can Someone help me fix this error the code is written in java... import java.util.*; class HPF { int at, bt, pri, pno; Process(int pno, int at, int bt, int pri) { this.pno = pno; this.pri = pri; this.at = at; this.bt = bt; }} class GChart { int pno, stime, ctime, wtime, ttime;} class MyComparator implements Comparator { public int compare(Object o1, Object o2) { Process p1 = (Process)o1; Process p2 = (Process)o2; if (p1.at < p2.at) return (-1); else if (p1.at == p2.at && p1.pri > p2.pri) return (-1); else return (1); }} class FindGantChart { void findGc(LinkedList queue) { int time = 0; TreeSet prique = new TreeSet(new MyComparator()); LinkedList result = new LinkedList(); while (queue.size() > 0) prique.add((Process)queue.removeFirst()); Iterator it = prique.iterator(); time =…