Write a program that takes five students' quizzes in a course. Consider each student has given ten quizzes. Find Best student Worst student Average student
Please check it and if it is wrong then give me a true solution.
Must focus on the average part.
Write a program that takes five students' quizzes in a course. Consider each student has given ten quizzes. Find
- Best student
- Worst student
- Average student
Solution:
#include <iostream>
int stu=5,quiz=10;
struct numbers
{
double students[5][10];
double average1[5];
double sumOfValues[5];
double best1=0;
}num;
using namespace std;
void best();
void worststudent();
void average();
int main()
{
for(int i=0 ;i<stu;i++)
{
cout<<endl<<"Enter student "<<i+1<<" data :"<<endl;
for(int j=0;j<quiz;j++)
{
cout<<"Quiz "<<j+1<<" numbers : ";
cin>>num.students[i][j];
cin.ignore();
}
}
best();
worststudent();
average();
return 0;
}
void best()
{
int best=0,o,p;
for(int i=0 ;i<stu;i++)
{
for(int j=0;j<quiz;j++)
{
if(best<num.students[i][j])
{
best=num.students[i][j];
o=i;p=j;
}
}
}
cout<<endl<<"Student "<<o+1<<" has best marks "<<num.students[o][p]<<" in quiz "<<p+1;
num.best1=num.students[o][p];
}
void worststudent()
{
int worststudent1,k,u;
for(int q=0 ;q<stu;q++)
{
for(int w=0;w<quiz;w++)
{
if(worststudent1>num.students[q][w])
{
worststudent1 =num.students[q][w];
k=q;u=w;
}
}
}
cout<<endl<<endl<<"Student "<<k+1<<" has worst marks "<<num.students[k][u]<<" in quiz "<<u+1;
}
void average ()
{
for (int i = 0; i < stu; ++i)
{
for (int j = 0; j < quiz; ++j)
{
num.sumOfValues[i] += num.students[i][j];
}
}
for(int i=0;i<stu;i++)
{
int * newArray = new int [stu*quiz];
num.average1[i] = (num.sumOfValues[i]) / (10 * ((stu*quiz)));
num.average1[i] *= 100;
}
int p=0;
for(int i=0;i<stu;i++)
{
if(num.average1[i]<num.average1[(i+1)%2]&&num.average1[i]>num.average1[(i-1)%2])
{
p=i;
}
}
cout<<endl<<endl<<"Student "<<p+1<<" is the Average ( "<<num.average1[p]<<"%) student .";
}
Step by step
Solved in 2 steps
