Write a program to count the number of 1’s in an 8-bit pattern and store it in memory at XX50 H. Also store the position of each 1 in memory locations starting at XX51 H.
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A: Required:- Assembly code handwritten with flow chart
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A: The, code has given below:
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A: The given data :
Assembly code with flow chart
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- Write a program in 8085 to find a summation of positive numbers for a set of numbers stored at memory locations from (3000 - 3020)H , then display the result of summation at port 00H.Write a program that asks the user to enter an unsigned number and read it. Then swap the bits at odd positions with those at even positions and display the resulting number. For example, if the user enters the number 9, which has binary representation of 1001, then bit 0 is swapped with bit 1, and bit 2 is swapped with bit 3, resulting in the binary number 0110. Thus, the program should display 6. using MIPS assembly codeWrite a program in 8085 to find a numbers which DI is 1 for aset of numbers stored at memory locations from (2000 - 2020)H, then store these numbers at M.L starting from (4000)H
- Write a MIPS program that asks the user to enter an unsigned number and read it. Then swap the bits at odd positions with those at even positions and display the resulting number. For example, if the user enters the number 9, which has binary representation of 1001, then bit 0 is swapped with bit 1, and bit 2 is swapped with bit 3, resulting in the binary number 0110. Thus, the program should display 6.Write a program that asks the user to enter and integer number and read it. Then ask him to enter a bit position (between 0 and 31) and display the value of that bit.(MIPS) srlv $s1,$s2,$s3 s2 = 3210 = 0000 0000 0000 1000 0000 0000 010 00002 s3 = 18 Bit = 10 1 = 00000000000000000000000000010000 2 = 00000000000000000000000000001000 3 = 00000000000000000000000000000100 4 = 00000000000000000000000000000010 5 = 00000000000000000000000000000001 S1 = 00000000000000000000000000000001 1 = 00000000000000000000000000000001 $t0 = 00000000000000000000000000000001 = x.1 = x AND $t0,$s1,1Given rax = 0x0000000200000100, rbx = 0x0000000000000100, and rcx = 0x0000000000000001,and the following values in memoryaddress -> byte at that address0x0000000000000100 -> 0x010x0000000000000101 -> 0x000x0000000000000102 -> 0x000x0000000000000103 -> 0x000x0000000000000104 -> 0x020x0000000000000105 -> 0x000x0000000000000106 -> 0x000x0000000000000107 -> 0x00what is the new value in %rax after the following operation?subq -0x04(%rbx, %rcx, 4), %rax
- Write a program to determine Y, where Y= (2X +5) Assume that X is an eight bits .stored in any memory locationWrite a MIPS program that asks the user to enter and integer number and read it. Then ask him toenter a bit position (between 0 and 31) and display the value of that bit.Write a MIPS assembly code program that asks the user to enter an unsigned number and read it. Then swap the bits at odd positions with those at even positions and display the resulting number. For example, if the user enters the number 9, which has binary representation of 1001, then bit 0 is swapped with bit 1, and bit 2 is swapped with bit 3, resulting in the binary number 0110. Thus, the program should display 6. Example of the MIPS assembly code I went the answer on MIPS Code only!!!!
- Given that a computer uses 4-bit ones’s complement numbers, what value will be stored in the variable j after the following code segment terminates? j = 1 k = -2 while(k != 0) { j = j + 1; k = k + 1; }Write a program in 8085 to find a summation of an even numbers for aset of numbers stored at memory locations from (5000 - 5020)H, then display the result of summation at port 00H.Consider the following hexadecimal readout: 000000 8A00 8E00 CFA1 48BF 7900 3202 9015 AD34 000010 0218 6D30 028D 3402 AD35 0288 3102 8D35 000020 0E30 0290 DAEE 3102 4C00 0200 0040 004B Refer to the first byte of memory shown above, address 000000. Assume that this byte is used to store an 8-bit unsigned integer. What is the decimal value stored in this byte? Group of answer choices 138 -27 22,842 66