Write a recursive function that takes a positive integer n as input. The function outputs the sum of the cubes of 1, 2, ... , to n. For example, on input 3, it should output 32. The function may not use: Loops , lists , sets , or dictionaries. Write it so that it does some error checking: While it can take any number as input, for any number besides a positive integer , it returns 0.
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- (Program) Write a program that tests the effectiveness of the rand() library function. Start by initializing 10 counters, such as zerocount, onecount, twocount, and so forth, to 0. Then generate a large number of pseudorandom integers between 0 and 9. Each time 0 occurs, increment zerocount; when 1 occurs, increment onecount; and so on. Finally, display the number of 0s, 1s, 2s, and so on that occurred and the percentage of time they occurred.Write a recursive fibonacci (n) function with an expression body. The function should return an Int; it will be too slow to deal with inputs whose fibonacci numbers are too large anyway. You do *not* need to use memoization. Note that: fibonacci(0) = 0 fibonacci(1) = 1 fibonacci(n, where n is greater than 1) = fibonacci(n-2) + fibonacci(n - 1)The Polish mathematician Wacław Sierpiński described the pattern in 1915, but it has appeared in Italian art since the 13th century. Though the Sierpinski triangle looks complex, it can be generated with a short recursive function. Your main task is to write a recursive function sierpinski() that plots a Sierpinski triangle of order n to standard drawing. Think recursively: sierpinski() should draw one filled equilateral triangle (pointed downwards) and then call itself recursively three times (with an appropriate stopping condition). It should draw 1 filled triangle for n = 1; 4 filled triangles for n = 2; and 13 filled triangles for n = 3; and so forth. API specification. When writing your program, exercise modular design by organizing it into four functions, as specified in the following API: public class Sierpinski { // Height of an equilateral triangle whose sides are of the specified length. public static double height(double length) // Draws a filled equilateral…
- In Kotlin A. Write a function lengthGreaterThan() with an expression body that takes a String s and an Int n and returns true if the String is at least n characters long. Then revise the function so that it can accept null values. If it receives null as the parameter, it should return false. B. Write a recursive function with an expression body that takes a list of nullable Strings and and Int an returns a list of just the Strings from the original list for which the function you wrote in the first part returns true C. Get the same result as in part B by using filter()Write a recursive function named decrypt, which takes a string s and a dictionary d where each key in the dictionary is a string word associated with a secret code as its key. This function should return the list of all possible ways (order it returns it in doesn’t matter) in which the string s can be decoded by splitting it into secret codes and separating the corresponding words of the decoded word with spaces. For instance, calling decrypt('turing', {'turing': 'A', 'tur': 'B', 'ing': 'C', 'tu': 'D', 'ring': 'E', 'ri': 'F', 'ng': 'G'}) returns ['A', 'D E', 'D F G', 'B C']. def decrypt(s: str, d: {str: str}) -> [str]:Below,enter code to complete implementation of a recursive function sum_all_integers(), which takes an input n and adds all intergers preceding it, up to n: add_all_integers(n):
- Write a recursive function that, given a sequence of comparable values, returns the count of elements where the current element is less than the following ( next ) element in the given sequence. See the examples given below. def count_ordered ( seq ) : """ Input : A sequence of comparable elements Output : The number of elements that are less than the following element in the sequence Example : >>> count_ordered ( [ 1 , 2 , 3 , 4 , 5 , 6 ] ) 5 >>> count_ordered ( ( 1 , 12, 7.3 , -2,4 ) ) 2 >>> count_ordered ( 'Python' ) 2 >>> count_ordered ( [ 6 ] ) 0 >>> count_ordered ( [ ] ) 0 """ In the first example above , count_ordered ( [ 1,2,3,4,5,6 ] )the returned answer is 5 because for all the first 5 numbers the current number is less than the next number. In the second example above, count_ordered ( ( 1,12,7.3 , -2,4 ) )the…Write a recursive function PrintPattern1 to print pattern that takes two integer arguments n and k. n is the starting number while k is the ending limit.Write a recursive function called print_num_pattern() to output the following number pattern. Given a positive integer as input (Ex: 12), subtract another positive integer (Ex: 3) continually until 0 or a negative value is reached, and then continually add the second integer until the first integer is again reached. For coding simplicity, output a space after every integer, including the last. Do not end output with a newline. Ex. If the input is: 12 3 the output is: 12 9 6 3 0 3 6 9 12 # TODO: Write recursive print_num_pattern() function if __name__ == "__main__": num1 = int(input()) num2 = int(input()) print_num_pattern(num1, num2)if (num1<=0): print(num1,end= '')
- This is for Java Write a recursive function that takes as a parameter a nonnegative integerand generates the following pattern of stars. If the nonnegative integer is 4,then the pattern generated is:**********Also, write a program that prompts the user to enter the number of lines inthe pattern and uses the recursive function to generate the pattern. Forexample, specifying 4 as the number of lines generates the above pattern. Java pleaseUsing recursion, write a Python function def countOdds(A) which which takes an array of integers A as input and returns the number of elements in the array that are odd. For example, if A is [1,2,5,3,6,5,3,5,5,4] the the function should return 7. If A is empty then it should return 3. Hint: To check if n is odd it suffices to check if dividing it by 2 gives remainder 1 (in Python, this remainder is calculated by n%2).Write a recursive function using python for the problem: A palindrome is a sequence of characters which is the same when the sequence is reversed. Given an array A indexed from p to q containing characters, determine if the sequence of characters in A[p..q] forms a palindrome. Return True is a palindrome is formed and return False if it does not.