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- Write and test a function removeDuplicates (somelist) that removes du-plicate values from a list.C++ Create a generic function add_bookends(ls, e) that adds a copy of element e to the front and back of list ls.Given two lists(List1, List2) of INTs create a third list such that should contain only odd numbers from the first list and even numbers from the second list def mergeList(listOne, listTwo): thirdList = [] #complete the function
- Write a function set_elements() that assigns 1 to the last and fifth elements of a list parameter. Ex: If the input is: One man's trash is another man's treasure then the output is: ['One', "man's", 'trash', 'is', 1, "man's", 1] ''' Your code goes here ''' vals_to_update = input().split() set_elements(vals_to_update) print(vals_to_update)Write the following function that sorts and merges two lists into a new sorted list. The new list contains only even numbers. def myMergeEvenList(list1, list2): Enter list1: 10,5,6,7 Enter list2: 12,8,5,0,1 The merged list is: 0,6,8,10,12Write a function that receives a list of words, then determines and displays in alphabetical order only the unique words. Treat uppercase and lowercase letters the same. The function should use a set to get the unique words in the list. Test your function with several sentences. Hint: use the set function on list comprehension.
- Write a function in_list that will take as its parameters an input list called mylist and a number. If the number is in the list the function should retun true, ottherwise, it should retun false. def in_list(mylist,number):struct node{int num;node *next, *before;};start 18 27 36 45 54 63 The above-linked list is made of nodes of the type struct ex. Your task is now to Write a complete function code to a. Find the sum of all the values of the node in the linked list. b. Print the values in the linked list in reverse order. Use a temporary pointer temp for a and b. i dont need a full code just the list partWrite a function REMOVE-NUM that takes a list and returns a list consisting of the original list with all numeric atoms removed. Examples: (REMOVE-NUM '(2 A 6 B 1 C 7 D)) returns the list (A B C D) (REMOVE-NUM '(3 A 4 B (1 E) 7 D)) returns the list (A B (E) D)
- Write a user defined function named as “length_list” function that finds the length of a list of list_node_t nodes. This code should fit with the following code.Partial Code: #include <stdio.h> #include <stdlib.h> /* gives access to malloc */ #define SENT -1 typedef struct list_node_s { int digit; struct list_node_s *restp; } list_node_t; list_node_t *get_list(void); int main(void) { list_node_t *x;int y; x=get_list(); printf("%d\n",x->digit); printf("%d\n",x->restp->digit); printf("%d\n",x->restp->restp->digit); // your length_list function should be called from here printf("Length is: %d",y); } /* * Forms a linked list of an input list of integers * terminated by SENT */ list_node_t * get_list(void) { int data; list_node_t *ansp; [20]scanf("%d", &data); if (data == SENT) { ansp = NULL; } else { ansp = (list_node_t *)malloc(sizeof (list_node_t)); ansp->digit = data; ansp->restp = get_list(); } return (ansp);Use the following code which adds and prints elements of a simply linked list, and add a member function that will duplicate nonzero value nodes in a list. Call your function properly in main and print the list again. #include <iostream> using namespace std; struct node { int data; node *next; node(int d,node*n=0) { data=d; next=n; } }; class list { node *head; public: list() { head=0; } void print() { for (node *t=head;t!=0;t=t->next) cout<<t->data<<" "; cout<<endl; } void add(int el) { head=new node(el,head); } }; void main() { list l; l.add(0); l.add(7); l.add(1); l.add(0); l.add(3); l.print(); }Define the function (siftNum lst). This function should resolve to all the numbers in the list, lst. For example: (siftNum '(a 8 2 1 m l 90 p 2)) resolves to '(8 2 1 1 90 2).