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Q: Write a C program to Find disjoint sets in a graph using disjoint set ADT operations FIND, UNION
A: The code is below:
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- Social Graph project is network which consists of two things : People is represented in the Graph by Nodes or Vertices (the vertex should consist of name of the person) Relationships is represented in the Graph by edges or arcsThe project should have at least two class with following methods : addNode add vertices to graphs(New person in the Graph Net )removeNode removes vertices to graphs(remove person from the graph Net)addEdge adds connections or paths between vertices in graphs(make new relationship between two persons in the graph )removeEdge removes connection or paths between vertices in graphs (remove the relationship between two persons in the graph )contains check if a graph contains a certain valuehasEdge checks if a connection or path exists between any two vertices in a graph IN JAVA LANGUAGE PLEASE and thnak you !modify this code to find the required output; graph={ 1: [2,3], 2: [1,3], 3: [1,2,5, 4], 4: [6,11,3,5], 5: [7,4,3], 6: [8,4], 7: [5,9], 8: [6], 9: [7,10], 10: [9,12], 11: [12,4], 12: [10,11] } #perform depth-first search def dfs(graph, start, visited, charge): #current node as visited visited.add(start) #Check the Roomba needs to enter the charging station if charge <= 6: print(f" {start} (Charging, {charge} Wh) -> ") charge =12 else: print(f"{start} (Cleaning, {charge} Wh) ->") charge -= 1 #Take he list of adjacent nodes adj_nodes = graph[start] #Visit the unvisited adjacent nodes for node in adj_nodes: if node not in visited: dfs(graph, node, visited, charge) #user to enter the starting node start_node = int(input ("Enter starting node: ")) # Perform depth-first search starting from the starting node visited = set() dfs(graph, start_node, visited, 12) # Sample outputEnter starting node: 11 (Cleaning, 12 Wh) ->2…JavaScript The jQuery "post" method that we used in this course to enable "round-trip" dialog with the node.js server has the form: $.post("/", x, y); Describe the type and purpose of the x and y parameters.
- THIS IS MY CODE HELP ME ACHIEVE POINTS OUTLINED BELOW : #include <stdio.h>#include <stdlib.h>#include <string.h>#include <float.h>#include "graph.h"#include "dijkstra.h" #define INFINITY DBL_MAX /* find shortest paths between source node id and all other nodes in graph. *//* upon success, returns an array containing a table of shortest paths. *//* return NULL if *graph is uninitialised or an error occurs. *//* each entry of the table array should be a Path *//* structure containing the path information for the shortest path between *//* the source node and every node in the graph. If no path exists to a *//* particular desination node, then next should be set to -1 and weight *//* to DBL_MAX in the Path structure for this node */Path *dijkstra(Graph *graph, int id, int *pnEntries){ int n; int i, j; int* nv = get_vertices(graph, &n); int *S = malloc(n * sizeof(int)); double *D = malloc(n * sizeof(double)); int *R = malloc(n…PYTHON PROGRAMMING Our goal in this problem is to determine the “lowest latency routes” starting from your location. The internet in this problem is modeled by a graph, with vertices corresponding to other clients or servers, and edges representing the links between clients/servers. Each edge is not undirected, i.e., the links are unidirectional. At the same time, each link adds a constant latency if you use the link in your routes. Note that if you need to communicate with your own client, then the latency is 0. We represent your location as the vertex 0. Your goal is to determine the total latency it would take if you used the shortest path route from your location to any other client/server in the network. Input Format Each test case starts with a line containing three integers V, E, and Q, denoting the number of vertices, edges, and queries, respectively. Note that vertices are identified with integers from 0 to V-1. E lines follow, each containing three integers s_i, d_i,…Compute the shortest path from node A to each of the other nodes. Then answer: What is the shortest distance from node A to node C and what was the last edge used to travel to C? Group of answer choices a. 6 is the distance, and B is the last edge used to travel to C along the shortest route b. 12 is the distance, and B is the last edge used to travel to C along the shortest route c. 6 is the distance, and E is the last edge used to travel to C along the shortest route
- Locate a sizable digraph online, such as a transaction graph in a system online or a digraph formed by links on web sites. Create a software called RandomRealDigraph that generates a graph by randomly selecting V vertices and E directed edges from the subgraph those vertices cause.Create a graph using networkx of CT towns that are within the red circle. For each town, output the shortest path to Fairfield. You can use networkx to get the shortest path. Output the number of cities using networkx Output the number of edges using networkx Submit python file or a jupyter notebook with all the code.Alert dont submit AI generated answer. Starting at node G, apply Depth Search and list out the nodes in the order inwhich they were visited. Please redraw the graph repeatedly inorder toshow your working.
- A star configuration of a network represents its structure as a graph with an edge from a single, central node to each remaining node. A point-to-point configuration represents a network as a complete graph. Draw a picture of an example of each kind of configuration with four nodes, and use big-O notation to state the efficiency of adding or removing a given node in each type of configuration. You can assume for now that removing each edge is a constant-time operation. *PythonSelect the term that best pairs with the definition. the link from a node to a child the number of edges on the path from the root to the node all nodes with the same depth is the largest depth of any node A. depth B. level C. edge D. heightThe node is a data structure that has three attributes; the head, the data and the link that could point to another node Select one: True False