Question
Asked Oct 13, 2019
Write an equation ​(a) in standard form and ​(b) in​ slope-intercept form for the line described. Through (3,7) and parallel to y=-6
check_circleExpert Solution
Step 1

Given,

           The line passes through the point (3,7) and parallel to y = -6.

Since, slope of the parallel lines are equal.

         y = -6

         y = (0) x -6

        Slope = 0

So, slope of the required line is 0.

Therefore, equation of the line passing through the point (3, 7) is

y – 7 = (0) (x – 3)

y – 7 = 0

      y = 7

Step 2

Part a

Therefore, equation of the line in the standard form is x (0) + y = 7.

Part b

Therefore, equation of the line in the slope-intercept is y = (0)x + 7.

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Tagged in

Math

Algebra

Equations and In-equations