Question
Asked Dec 9, 2019
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Write an expression for a transverse harmonic wave that has a wavelength of 2.1 m and propagates to the right with a speed of 13.8 m/s . The amplitude of the wave is 0.15 m , and its displacement at t=0 and x=0 is 0.15 m .

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Expert Answer

Step 1

Step 1

Harmonic wave is any wave which has repetitive frequency with respect to some initial wave. The transverse harmonic wave is the one which travels in the transverse direction.

The wave equation is given as

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y(t) = Asin(@r + ø)

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Step 2

Step 2

It is given that

Now,

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2 = 2.1m v =13.8m/s A = 0.15 m y(0) = 0.15 m at t = 0,x = 0 f = 13.8 2.1 = 6.57/s

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Step 3

Step 3

Put these values in the main eq...

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) = 27 f = 2¤(6.57) = 41.26 /s y(t) = A sin(@t + ø) y(0) = 0.15 sin(0 + ø) 0.15 sin(ø) = =D1 0.15 Ø = sin-'(1) Ø =

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