Write and evaluate the definite integral that represents the area of the surface generated by revolving the curve about the x-axis. y = 1 3 x3 The x y-coordinate plane is given. A curve is rotated about the x-axis to form a surface. The curve is labeled y = (1⁄3)x3. The curve starts at the origin, goes up and right getting more steep, and ends at the point (3, 9).
Write and evaluate the definite integral that represents the area of the surface generated by revolving the curve about the x-axis. y = 1 3 x3 The x y-coordinate plane is given. A curve is rotated about the x-axis to form a surface. The curve is labeled y = (1⁄3)x3. The curve starts at the origin, goes up and right getting more steep, and ends at the point (3, 9).
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 67E
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Question
Write and evaluate the definite integral that represents the area of the surface generated by revolving the curve about the x-axis.
y =
1
3
x3
The x y-coordinate plane is given. A curve is rotated about the x-axis to form a surface.
The curve is labeled y = (1⁄3)x3.
The curve starts at the origin, goes up and right getting more steep, and ends at the point (3, 9).
2?
3
dx
0
=
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