Write the expression for Keq for the following reactions. In each case indicate whether the reaction is homogeneous or heterogeneous.(a) N2(g) + 3 H2(g) 2 NH3(g)Keq = PNH32 / (PN2 PH23)Keq = (PN2) (3 PH2) / 2 PNH3 Keq = PN2 PH23 / PNH32Keq = 2 PNH3 / ((PN2) (3 PH2))The reaction is (b) 4 HCl(g) + O2(g) 2 H2O(l) + 2 Cl2(g)Keq = PHCl4 PO2 / PCl22Keq = 2 PCl2 / (4 PHCl PO2) Keq = 4 PHCl PO2 / 2 PCl2Keq = PCl22 / (PHCl4 PO2)The reaction is (c) H2(g) + I2(g) 2 HI(g)Keq = 2 PHI / (PH2 PI2)Keq = PH2 PI2 / 2 PHI Keq = PH2 PI2 / PHI2Keq = PHI2 / (PH2 PI2)The reaction is

We can write keq by recalling this equation A + B ---> C + D Keq =( Pc × PD) / (PA × PB) Px =…

Write the expression for Keq for the following reactions. In each case indicate whether the reaction is homogeneous or heterogeneous. (a) N2(g) + 3 H2(g) 2 NH3(g) Keq = PNH32 / (PN2 PH23) Keq = (PN2) (3 PH2) / 2 PNH3 Keq = PN2 PH23 / PNH32 Keq = 2 PNH3 / ((PN2) (3 PH2))

Write the expression for Keq for the following reactions. In each case indicate whether the reaction is homogeneous or heterogeneous. (a) N2(g) + 3 H2(g) 2 NH3(g) Keq = PNH32 / (PN2 PH23) Keq = (PN2) (3 PH2) / 2 PNH3 Keq = PN2 PH23 / PNH32 Keq = 2 PNH3 / ((PN2) (3 PH2))

Chemical Principles in the Laboratory

11th Edition

ISBN:9781305264434

Author:Emil Slowinski, Wayne C. Wolsey, Robert Rossi

Publisher:Emil Slowinski, Wayne C. Wolsey, Robert Rossi

Chapter21: Rates Of Chemical Reactions, Ii. A Clock Reaction

Section: Chapter Questions

Problem 2ASA

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Question

Write the expression for K_eq for the following reactions. In each case indicate whether the reaction is homogeneous or heterogeneous.

(a) N₂(g) + 3 H₂(g) 2 NH₃(g)

K_eq = P_NH3² / (P_N2 P_H2³)

K_eq = (P_N2) (3 P_H2) / 2 P_NH3

K_eq = P_N2 P_H2³ / P_NH3²

K_eq = 2 P_NH3 / ((P_N2) (3 P_H2))

The reaction is

(b) 4 HCl(g) + O₂(g) 2 H₂O(l) + 2 Cl₂(g)

K_eq = P_HCl⁴ P_O2 / P_Cl2²

K_eq = 2 P_Cl2 / (4 P_HCl P_O2)

K_eq = 4 P_HCl P_O2 / 2 P_Cl2

K_eq = P_Cl2² / (P_HCl⁴ P_O2)

The reaction is

(c) H₂(g) + I₂(g) 2 HI(g)

K_eq = 2 P_HI / (P_H2 P_I2)

K_eq = P_H2 P_I2 / 2 P_HI

K_eq = P_H2 P_I2 / P_HI²

K_eq = P_HI² / (P_H2 P_I2)

The reaction is

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