Write the missing instructions to complete the codes for Sleeping Barbers problem solution: Shared data: customer = 0, barber = 0, mutex = 1; int waiting = 0; CHAIR = 5; Barber Customers while ( TRUE ){ wait ( mutex ); if ( waiting < CHAIR) { waiting + +; signal ( customer ); while (TRUE) { customer ); wait ( mutex ); waiting - -; signal ( barber ); signal ( mutex ); mutex ); wait ( ): cut hair(); get haircut(); } else signal ( mutex);
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- The city of BeeOS has a sightseeing tour which departs from a bus stop, takes a city tour and arrives at the same bus stop. There is only one bus that takes these tours indefinitely. The city visitors wait at the bus stop to board the bus, which can hold maximum N people. Each visitor should queue up at the bus stop and not get on until the bus starts its engine. The bus should wait until N visitors have boarded before departing. The bus can start its tour only when it is full. Once the bus has finished the trip, the visitors should get off after the bus stops its engine. All visitors should leave before the bus starts again. The process codes to be run by the bus and visitors are given below without any synchronization. Note that ‘Visitor’ code will be called by each visitor separately.Bus{loop{start_engine();take_tour();stop_engine();}}Visitor{get_on();get_off();}Rewrite the Bus and Visitor codes, with convenient mutex and/or semaphore operations, such that all synchronization…A staff number of a BigHit company is composed of 2 non-vowels uppercase alphabets and 3 digit mumbers. i How many staffnumbers can be generated if the company requested to start the first letter with J and the 3 digit numbers (repetition not allowed)? ii. How many ways the staff number can be formed if it has any consonants and odd numbers with repetition allowed?PROBLEM IN IN PYTHON 3. THIS IS A CODING PROBLEM. NOT A MULTIPLE CHOICE PROBLEM. ANSWER SHOULD BE IN PYTHON. IF YOU DO NOT KNOW HOW TO SOLVE AND THINK IT IS A MULTIPLE CHOICE PROBLEM, DO NOT ANSWER. class Solution: """ RAW_TRADE_HEADER = ["trade_id", "trade_date", "time_of_trade", "portfolio", "exchange", "product", "product_type", "expiry_dt", "qty", "strike_price", "side"] """ def process_raw_trade(self, raw_trade: List): def run(self) -> List[Tuple[str, str]]:
- "Equatable and Comparable" in the Swift Programming: The Big Nerd Ranch Guide (2nd Ed.) e-book: Point’s current conformance to Comparable yields some confusing results. let c = Point(x: 3, y: 4) let d = Point(x: 2, y: 5) let cGreaterThanD = (c > d) // false let cLessThanD = (c < d) // false let cEqualToD = (c == d) // false As the above example demonstrates, the trouble arises in comparing two points when one point’s x and y properties are not both larger than the other point’s. In actuality, it is not reasonable to compare two points in this manner. Fix this problem by changing Point’s conformance to Comparable. Calculate each point’s Euclidean distance from the origin instead of comparing x and y values. This implementation should return true for a < b when a is closer to the origin than b. Use the formula shown in below Figure 25.1 to calculate a point’s Euclidean distance. Figure 25.1 Euclidean distance Euclidean distanceThe Dining Philosopher solution using monitors shown in the code snippet below does not suffer from deadlock. However, starvation is still possible. Explain in details why. Each philosopher i invokes the operations pickup() and putdown() in the following sequence: DiningPhilosophers.pickup(i); EAT DiningPhilosophers.putdown(i);Correct answer will be upvoted else downvoted. game expert just permits him to pose one kind of inquiry: Little Dormi picks a hub r (1≤r≤n), and the game expert will answer with an exhibit d1,d2,… ,dn, where di is the length of the most brief way from hub r to I, for all 1≤i≤n. Furthermore, to make the game out of line challenge Little Dormi the game expert will permit all things considered ⌈n2⌉ questions, where ⌈x⌉ signifies the littlest integer more noteworthy than or equivalent to x. Confronted with the stomach-agitating chance of not having the option to figure the tree, Little Dormi needs your assistance to devise a triumphant methodology! Note that the game expert makes the tree before the game beginnings, and doesn't transform it during the game. Input The principal line of input contains the integer n (2≤n≤2000), the number of hubs in the tree. You will then, at that point, start communication. Output At the point when your program has discovered…
- The problem states that there are five philosophers sitting around a circular table. The philosophers must alternatively think and eat. Each philosopher has a bowl of food in front of them, and they require a fork in each hand to eat. However, there are only five forks available. You need to design a solution where each philosopher can eat their food without causing a deadlock.Please solve max 30 minutes thank u Boolean Satisfaction Problem Boolean Satisfiability Problem (SAT) (https://en.wikipedia.org/wiki/Boolean_satisfiability_problem) is one of the most important problems in Computer Science. SAT is a problem that has NP-Complete complexity, where the only way to solve the problem is to try all the possibilities and check which one is correct. [LO 1, LO 2, LO 3 & LO 4,] Briefly explain how you use Strongly Connected Component (SCC) to solve the special case of the Boolean Satisfiability Problem, namely 2-SAT (https://en.wikipedia. org/wiki/2-SAT) . This solution has linear complexity. NOTE LO1: Explain fundamental concept of analysis arithms. LO2: Apply algorithm techniques and methods. LO3: Solve a problem using specific algorithm. LO4: Compare several algorithm design methodsb) Simulate a dynamic programming algorithm for a rod with prices of < 2 4 8 12 13 >. Organize your work in a table with appropriately labeled columns. Identify the cuts. Pseudo code for cutRod() appears after number 4. please show in table.
- [Medium] Suppose, you have been given a non-negative integer which is the height of a ‘house of cards’. To build such a house you at-least require 8 cards. To increase the level (or height) of that house, you would require four sides and a base for each level. Therefore, for the top level, you would require 8 cards and for each of the rest of the levels below you would require 5 extra cards. If you were asked to build level one only, you would require just 8 cards. Of course, the input can be zero; in that case, you do not build a house at all. Complete the recursive method below to calculate the number of cards required to build a ‘house of cards’ of specific height given by the parameter. public int hocBuilder (int height){ // TO DO } OR def hocBuilder(height):Wireless sensor networks are a special kind of network that facilitates communication. Sensor nodes in WSNs relay information to and from a central base station. The computing resources and storage space of a sensor node are limited. Take, for example, an algorithm that can be solved by solving subproblems. Is it preferable to use dynamic programming or divide and conquer to solve these subproblems independently at various sensor nodes? Try to keep your writing short and sweet.After finding out you are secretly part of the royal family of Genovia, you inherit a 16th-century Genovian castle with an elaborate plumbing system that has accumulated pipes, junctions, and clogs over four centuries. Instead of a diagram, you are given a list of pipes and their capacities leading from the water source to your bathroom Pipes S,2 S,4 2,3 2,5 4,2 4,5 3,5 3,6 5,6 5,7 6,7 6,T 7,T Capacity 4 7 6 2 4 3 6 2 5 4 1 9 4 You'd like to know if it is safe to install a modern shower, or if this will eventually overflow the historic bathtub. Use the Ford Fulkerson algorithm to determine the max flow of this flow network/graph. Please draw your final residual graph and write the calculated max flow.