Write the output produced by the method when it is passed this ArrayList: [5, 17, 23, -7, -3, 11, 13]
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- JAVA plese Implement the indexOf method in the LinkedIntegerList class public int indexOf(int value); /** * Returns whether the given value exists in the list. * @param value - value to be searched. * @return true if specified value is present in the list, false otherwise. */ } public static void main(String[] args) { // TODO Auto-generated method stub SimpleIntegerListADT myList = null; System.out.println(myList); for(int i=2; i<8; i+=2) { myList.add(i); } System.out.println(myList.indexOf(44));Write a code in python. Write down only the methods that are required; testers are not required. Complete the method below that takes the reference of a non-dummy headed singly linear linked list and removes all the nodes containing multiples of 5 from the list. remove_multiple_of_five(head)import java.util.ArrayList;import java.util.Arrays;public class PS{/*** Write the method named mesh.** Start with two ArrayLists of String, A and B, each with* its elements in alphabetical order and without any duplicates.* Return a new list containing the first N elements from the two* lists. The result list should be in alphabetical order and without* duplicates. A and B will both have a size which is N or more.* Your solution should make a single pass over A and B, taking* advantage of the fact that they are in alphabetical order,* copying elements directly to the new list.** Remember, to see if one String is "greater than" or "less than"* another, you need to use the compareTo() method, not the < or >* operators.** Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]** @param a an ArrayList of String in alphabetical order.* @param b an…
- Java/Data Structures: If myList is a declared ADT list and the front of the list is on the left, what does the method getEntry(3) return after applying the following pseudo code? myList.add(“horse”) myList.add(“goat”) myList.add(1, “fish”) myList.add(“cat”) myList.add(2, “dog”) myList.remove(4) Multiple choice. A) cat B) dog C) fish D) horsein java Write a method for the Linked Based List class which returns the largest item in the list. If the list is empty return null. Assume that class T is Comparable.DO NOT USE ANY OTHER METHODS OF THE LINKED BASED LIST CLASS. What is the worst case and best case complexity of the code in the previous problem? Explain your answer.Consider a singly linked list data structure as show below, implement the most efficient algorithm to detect whether the elements in the list form a palindrome or not, the method must return true/false accordingly. class SinglyList: class _Node: def __init__(self, e, next): self._element = e self._next = next def __init__(self): self._head = self._tail = None def is_palindrome(self)->bool:
- Write a Java class myLinkedList to simulate a singly linked list using arrays as the underlying structure. Include the following methods: 1. insert an element within the linked list.(this should also work for the front and the rear of the list) 2. Remove an element from the linked list 3. Display (print) the elements of the linked list in order. 4. A method to check if the list is "empty". Test your solution using a linked list that initially has the characters A, B, D, E, F, and G. Insert "C" between B and D. Remove element "F". [Hint: One solution (recommended) is to use 2 arrays. One for the data, and the other for the "next" pointer. Also, consider using dummy nodes for the front, and possibly the rear of the list] Extend the solution so that it simulates a doubly linked list! (hint: You will need a third array to represent the "backward" pointers)Assume that lists are implemented using an array. For each of the following List methods, say whether (in the worst case) the number of operations is independent of the size of the list (is a constant-time method), or is proportional to the size of the list (is a linear-time method)• the constructorPlease give me the proper answer with step by step solution Qns:Java question Implement a method that adds a value in a linked list using recursion and using this signature: public void addValue(int value)
- Java - Given a list (44, 80, 96, 33, 15, 42, 73, 99, 91, 77) and a gap array of (5, 4, 1):import java.util.ArrayList;import java.util.Arrays; public class PS07A{/*** Write the method named mesh.* * Start with two ArrayLists of String, A and B, each with * its elements in alphabetical order and without any duplicates. * Return a new list containing the first N elements from the two * lists. The result list should be in alphabetical order and without * duplicates. A and B will both have a size which is N or more. * Your solution should make a single pass over A and B, taking * advantage of the fact that they are in alphabetical order, * copying elements directly to the new list.* * Remember, to see if one String is "greater than" or "less than" * another, you need to use the compareTo() method, not the < or > * operators. * * Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]* * @param a an ArrayList of String in alphabetical…Java Design and draw a method called check() to check if characters in a linked list is a palindrome or not e.g "mom" or "radar" or "racecar. spaces are ignored, we can call the spaces the “separator”. The method should receive the separator as a variable which should be equal to “null” when no separator is used.