Write the state of the elements of the vector below after each of the first 4 passes of the outermost loop of the insertion sort algorithm. (After the first pass, 2 elements should be sorted. After the second pass, 3 elements should be sorted. And so on.) // index 0 1 2 3 4 5 6 7 vector numbers{29, 17, 3, 94, 46, 8, -4, 12}; insertionSort(numbers); NOTE: Write your answer inside curly braces with numbers separated by commas {29, 17, 3, 94, 46, 8, -4, 12} after pass 1 after pass 2 after pass 3 after pass 4

Write the state of the elements of the vector below after each of the first 4 passes of the outermost loop of the insertion sort algorithm. (After the first pass, 2 elements should be sorted. After the second pass, 3 elements should be sorted. And so on.) // index 0 1 2 3 4 5 6 7 vector numbers{29, 17, 3, 94, 46, 8, -4, 12}; insertionSort(numbers); NOTE: Write your answer inside curly braces with numbers separated by commas {29, 17, 3, 94, 46, 8, -4, 12} after pass 1 after pass 2 after pass 3 after pass 4

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter12: Points, Classes, Virtual Functions And Abstract Classes

Section: Chapter Questions

Problem 29SA

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Write the state of the elements of each of the following arrays after each pass of the outermost loop of the selection sort algorithm has occurred (after each element is selected and moved into place).int[] numbers1 = {63, 9, 45, 72, 27, 18, 54, 36};int[] numbers2 = {37, 29, 19, 48, 23, 55, 74, 12};
Trace each pass of selection, insertion, and quick sort for the list of values below. For quick sort, assumethat the pivot is the middle value in the portion of the array to be sorted. If there are an even number ofitems in the unsorted part of the list, so that two values “tie” for the middle value, pick the one on theleft as the pivot.The numbers are: 6, 3, 11, 4, 9, 8, 17 ,7
this function c++ accept vector , replace this vector to array void merge_sort_4(vector<int> lst,int start,int end){if (start < end){int quarter1 = (start + end) / 4;int quarter2 = (start + end) / 2;int quarter3 = (end - quarter1 - 1); merge_sort_4(lst, start, quarter1);merge_sort_4(lst, quarter1 + 1, quarter2);merge_sort_4(lst, quarter2 + 1, quarter3);merge_sort_4(lst, quarter3 + 1, end); merge4(lst, start, quarter1, quarter2, quarter3, end);}}void merge4(vector<int> lst,int start,int q1,int q2,int q3,int end){vector<int> first_q_list;for(int i=start;i<q1+1;i++)first_q_list.push_back(lst[i]);vector<int> sec_q_list;for(int i=q1+1;i<q2+1;i++)sec_q_list.push_back(lst[i]);vector<int> third_q_list;for(int i=q2+1;i<q3+1;i++)third_q_list.push_back(lst[i]);vector<int> last_q_list;for(int i=q1+1;i<end+1;i++)last_q_list.push_back(lst[i]);int…
Implement a shellsort variant where the increment sequence is stored in an array rather than being computed.
Q1)Suppose you are given an array A of n elements. Your task is to sort n numbers stored in array A by reading the first element of A and placing it on its original position (position after sorting). Then read the second element of A, and place it on its original position. Continue in this manner for the first n-1 elements of A. What type of sorting is this? Write the algorithm and also mention the name of this sorting algorithm. What loop invariant does this algorithm maintain? Give the best-case and worst-case running times of this sorting algorithm. Q2)Consider an array consisting of the following sequence: 1, 4, 9, 16, 25, 49, …, n Suppose a number in the sequence is missing. Write the mathematical process to find the missing number, i.e. some equation. What is the time complexity of finding the missing number in the sequence? Q3)Sort the text “SARHAD UNIVERSITY” in ascending order using the insertion sort algorithm. Discuss also the best, worst and average case complexity of the…
Implement bubble sort, selection sort iteratively, and recursively. Implement linear search. Familiarize with C++ STL class vector Program Execution: The following example illustrates how your program should work. The program first reads the length of the vector (as 5 in example below), then reads this number of integers, and push them into a vector. The program then reads a command (selection, bubble, rselection, rbubble), and call the corresponding sorting function to sort the vector. The vector after being sorted will be displayed. Note that the user input are underscored. [storm:]$ g++ lab1.cpp -o lab1.exe [ storm:]$ ./lab1.exe 5 74 25 32 99 24 selection 24 25 32 74 99 [storm:]$ ./lab1.exe 317 5 23bubble 5 17 23 General Hints:* Write your main function first. * Incrementally write one function and test it before moving to the next. Please refer to the slides on how to implement these functions. 1. selection: iterative selection sort function bubble: iterative bubble…
Q1: Suppose you are given an array A of n Your task is to sort n numbers stored in array A by reading the first element of A and placing it on its original position (position after sorting). Then read the second element of A, and place it on its original position. Continue in this manner for the first n-1 elements of A. What type of sorting is this? Write the algorithm and also mention the name of this sorting algorithm. What loop invariant does this algorithm maintain? Give the best-case and worst-case running times of this sorting algorithm.
please convert the code to C language //C++ program to check if two arrays //are equal or not #include <bits/stdc++.h>using namespace std; bool similar_array(vector<int> arr1, vector<int> arr2){ //create teo different hash table where for each key //the hash function is h(arr[i])=arr[i] //we will use stl map as hash table and //will keep frequency stored //so say two keys arr[0] and arr[5] are mapping to //the same location, then the location will have value 2 //instead of the keys itself //if two hash tables are exactly same then //we can say that our arrays are similar map<int, int> hash1; map<int, int> hash2; //for each number for (int i = 0, j = 0; i < arr1.size(); i++, j++) { hash1[arr1[i]]++; hash2[arr2[i]]++; } //now check whether hash tables are exactly same or not for (auto it = hash1.begin(), ij = hash2.begin(); it != hash1.end() && ij != hash2.end(); it++, ij++) {…
NEED IT IN VECTORS, NOT ARRAYS Implement InsertionSort function either iteratively or recursively: For iterative implementation: // You are required to use BinarySearch in your implementation of InsertionSort void InsertionSort (vector<int> & list) { } //Recursive Insertion Sort to sort list[first...last] recursively //You need to use BinarySearch void InsertionSort (vector<int> & list, int first, int last) { }
Following is the function for interpolation search. This searching algorithm estimates the position (index) of a key in array based on the elements in the first position and last position in the array, and the length of array. The array must be sorted in ascending order. Suppose array A contains the following 15 elements: A = [1, 3, 3, 10, 17, 22, 22, 22, 24, 25, 26, 27, 27, 28, 28] At first iteration, at which position (index) the element of 24 is estimated in array A? In which part of array (starting index and ending index) the searching should continue? How many iterations the searching are performed until the element of 24 is found? int InterpolationSearch(int x[], int key, int n) { int mid, min = 0, max = n-1; while(x[min] < key && x[max] > key) { mid = min + ((key-x[min])*(max-min)) / (x[max]-x[min]); if(x[mid] < key) min = mid + 1; else if(x[mid] > key) max = mid - 1; else return mid; } if…
create an array of 30 random numbers that range between 1and 100. And yet again, write a function that will receive a number from the userand determine if that number exists in the array or not. But this time, start bySORTING your input list. After a sort, the list in problem 1 is as follows:[2, 2, 3, 5, 12, 14, 14, 15, 23, 36, 39, 41, 44, 44, 45, 48,49, 50, 52, 52, 59, 71, 81, 82, 88, 89, 89, 93, 96, 97] Approach: Implement a method called findC(x, A, i, j), where x is the number we arelooking for in array A, the first index of the array is i and the last index is j. We wantto determine whether x exists in A anywhere between index i and index j. Your firstcall to this method will therefore look like this: findC(x, A, 0, A.length-1). In the body of your function, compare x with the item that is in the middle of thearray, as you did before. As before, call the middle of index of the array mid. But thistime, if x<=a[mid], recursively call your function to search ONLY the first half of…