ww 25 2 ww 82 50 2 50 2 ww ww

Q: 30 Ω 40 2 8Ω ww- ww 60 Ω 202 10 Ω 50 2 ww ww

A: To solve above problem, one should know how to find equivalent resistance for series and parallel…

Q: 5Ω 3 A 162 10Ω E 12 V ww

A:

Q: 5 A 20 2 w- 25 2 160 -W- a 472 18 Q b

A: Given circuit,

Q: sa 30 30 V ww 20 40 15 V ww ww

A:

Q: R =1 kf R2=1 kl Ry = 3 k 14 R Rs 6 kN R = 2 k

A: We will use nodal analysis to to calculate the Current I1,I2,I3,I4,I5 and I6 Let the voltages at…

Q: 30 Ω 10 Ω 20 Ω ww ww ww 90 V 60 Ω 6Α 30 Ω 40 V

A: From the super position principle

Q: 30 Ω 40 Ω 82 a oww- ww ww * 60 2 20 2 10 2 50 Ω boww- ww 80 Ω 70 Ω ww ww

A: This network is combination of series and parallel connection.  Equivalent resistance across a and b…

Q: 10 2 2Ω 6 V 1Ω iz 13 502 8 V ww 5.

A:

Q: ww a 20 Ω 18 2 ΙΩ Rab b. ww-

A: To solve above problem, one should know how to find equivalent resistance for series and parallel…

Q: 8 A 1=0 ox. 12 352 W SH 20

A:

Q: 20 k2 50 k2 ww 10 k2 ww 72

A: To answer the above question, one should know what an amplifier is. An amplifier is an electronic…

Q: Given :- 385 Gea 4s 25 12

A: Let's solve for the equivalent Geq by using the network reduction techniques. Care must be taken so…

Q: *.لأقصی قوة R احسب قيمة نقطة 1 20 2 20 2 20 V R. 10 2 اجابتك ww

A:

Q: 120 120 120 24v ww 240 d 80 20 ww ww ww-

A: Applying the nodal analysis at node c:

Q: 12 50 ww 1 V 8Ω 3Ω lo = A Vo = mv (+1

A:

Q: 22 3 2 ww ww ww 6Ω 6Ω ο + (+1

A: In this question we will find source voltage...

Q: 502 ww- 20Ω 30 2 12 V 15 Q 20 2 30 V ww 20 V 60, 80 2 ww

A: 150-400-8004065-301500-30500-20-8015095000-20080

Q: + 32 V -8 + 2 ww +1

A: Redrawing the given circuit by assuming a loop current in the circuit:

Q: 82 ww 6 V ЗА

A: The given circuit is

Q: 10 Ω 24 2 50 Ω ww 25 2 15 V 20 Ω 30 2 60 Q 20 Q ww ww

A:

Q: 10 4 ww TV 25 15 fig. 1 20 ww

A: Given: Power dissipated in 20Ω resistor is 180 W. Then,     P=I42×R180=I42×20I42=18020I42=9    I4=3…

Q: 40 ww 202 Fig.6 2 A 10 ww F 20 V b IL

A: Given circuit diagram, Vth=? Rth=?

Q: 20 Ω 50 μF 10 mH ww- ell 10 cos 10°r V 202 4i, 30 2 ww

A:

Q: 1.2 2 ww 4Ω 20 A 2Ω 8Ω 12 Ω 3Ω 6Ω Figure 2.87 ww ww ww ww

A: Here i have done source teansformation technique and found the value of the power and Vx.

Q: 1 k2 32 kN +) 2 V 1 k2 12 V 2 kn 4 mA 6 V 2 k 6 mA Vo ww

A: NODAL ANALYSIS: Nodal analysis is a generic technique for evaluating circuits that use node voltages…

Q: ww 12 12Ω ww- 20 V ww 10 2 50 ww Rea

A: According to the question we have to calculate Req and I.

Q: 22 25 V 123 3 V

A: The given figure is shown below:

Q: +1 Vs 6Ω ww 3ΩΣ ΖΩ Is

A: Given data, Vs=5 V, is=10 A Circuit diagram is given as,

Q: 30 ww ww 3A 10 2 15 V ww

A:

Q: 10 50 4Ω 12 V 2H 2 +. 'C 1F ww-

A: Here, source is a dc voltage source. So the capacitor will behave as open circuit and inductor will…

Q: 20 Ω 60 Ω 20 V 10 2 50 2 20 Ω ww (A) ww ww

A: To solve above problem, one should know about Kirchhoff's lawThere are two Kirchhoff's law.KCL: It…

Q: 8K Ow www 2K ww 54K 12k www 6k ww 12K

A:

Q: 6Ω 62 a ww ww 12 V 2 A 3 42 b (+)

A:

Q: 60 S2 ww ww ww 100 2 100 2 ww 150 2

A: In this question ,we have to find equivalent resistance across points a-b and c-d...

Q: 60 Ω 12Ω 6Ω 2.5 Ω ww 80 2 15Ω 20 Ω Rea

A: To solve above problem one should know the equivalent resistance calculation of series and parallel…

Q: 24S Gea 手5 325 122

A: Here i have converted delta to star and found the answer.

Q: 80 2 242 50 2 ww ww 250 20 a 30 a v. 20 V 20 A Figure 1 ww-

A: Given: V=20 V Circuit :-1

Q: 2 2 ww 2 A 62 5Ω 4 2 4 A ww ww ww

A:

Q: 60 Ω ww 12Ω 50 ww ww , 30Ω 80 2 40 V 15 Q 20 2 Reg

A:

Q: 20 kn 60 kf 120 k2 t0.1 mA

A: Given figure Applying nodal analysis  V-Vs20+V120+V60=0V120+1120+160=Vs20V9120=Vs209V=6Vs.........1

Q: 50 2 80 2 ww 24 2 ww 25 a 20 V 20 2 30 2 602 20 2 ww

A:

Q: 20 2 15Q ww 42 150 ww ww ww 50 ww 15Q 48 V 24 2 ww ww

A:

Q: 741 40 k 5 kQ 20 k2 ww

A:

Q: 12 ww- ww 10Ω d a o Ww 62 ww Rab 3Ω 42 50 ww 122 9.

A:

Q: 12 5A 4S ww 48 4 3S 2A ww

A:

Q: SS ww Ge 6 S 12 S ww

A:

Q: 20 20 ww 82 13 A ww

A: