ww im R1 V I sine î sine In the above circuit, let R1 = 8 ohm, reactance of L1 be j12 ohm. RMS value of the voltage source is 180 volt at phase angle 0 degree. The voltage source supplied 2.5 KW and 0.4 kVaR power. Determine the current source value in complex phasor form. Re()= ampere Im(1) = ampere

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.16P: A single-phase, 120V(rms),60Hz source supplies power to a series R-L circuit consisting of R=10 and...
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ww
R1
I
V
sine
sine
In the above circuit, let R1 = 8 ohm, reactance of L1 be j12 ohm. RMS value of the voltage source is 180 volt at phase angle 0 degree. The voltage source supplied 2.5 KW and 0.4 kVaR power.
Determine the current source value in complex phasor form.
Re()=
ampere
Im(1)
=
ampere
ell
L1
Transcribed Image Text:ww R1 I V sine sine In the above circuit, let R1 = 8 ohm, reactance of L1 be j12 ohm. RMS value of the voltage source is 180 volt at phase angle 0 degree. The voltage source supplied 2.5 KW and 0.4 kVaR power. Determine the current source value in complex phasor form. Re()= ampere Im(1) = ampere ell L1
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