(x – 6)? + (y + 5)? = 16 In the xy-plane, the graph of the equation above is a circle. Point P is on the circle and has coordinates (10, –5). If PQ is a diameter of the circle, what are the coordinates of point Q ?

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A: Substitute y=36 and find value of x then find solution.

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A: According to the problem, we have

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A: Solution...

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A: Substitute h,k and r in the equation, x-h2+(y-k)2=r2 and solve for y to yield the result.

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Q: Q4: An equation for the circle with the given center C(-3, 0) and radius a = 3 is x^2 + 6x + y^2 = 0…

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