- x dx – 2 x 1 + e 2)

Q: 1. (r - y2) dx = 2xy dy %3D

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Q: 3. Evaluate yn x dx

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Q: S Evaluate: A None 1 dx (x-3)2 (в B D -I (E) ∞ (does not exist)

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Q: Evaluate xe-X dx, if it exists. O 1) 1/2 2) 1 3) 1-e 4) It does not exist.

A: We have to evaluate given integral

Q: .3 1 J2 dx=? x² – 4x+5

A:

Q: 1. Find (2x – e") dx e*) dæ

A: Please specify which part is to be solved. In this question we have to find the integral,  (1)…

Q: y = [e2* + (x + In x)³1* %3D

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Q: L,sgn(x) dx = 1. 0 2. 2 3. -2 4. 1 2 O 1 3 O 4 O

A: (1)…

Q: 1 dx. | z(x² + 2x + 2)

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Q: dx dx Therefore, 1 f '(x) = 1 + 1 + (x - 2

A: Solution is given below....

Q: (c) [ n@dx In(x) dx x2

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Q: (2+ e-#/») d.x +2 (1 -) dy = 0

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Q: 2) solve the ode: dx - (x + y + 1)dy = 0

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Q: 4cos (x)dx =

A: detailed solution is given below

Q: e2 1 dx x In x e

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Q: S* (1– x)e* dx

A: To find out the integration.

Q: 1. fE dx = In]x| - e* + C %3D

A: Note:- For this problem, nothing is mentioned but i think you want value of question mark, so…

Q: x dx 5. J 3-x2-6x

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Q: 1-e dx +2(xe – y)dy = 0;

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Q: e*dx + 2 | 2*dx = e*+1 2*+1 + + C, In 2

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Q: 2x-x ca ch(y) 3 dy dx = 3 dx dy, then If (A)5, 0 2a+g(1)+2h(0)=

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Q: 4. (1 + e) dx + e(1) dy x (1) dy = 0 [Answer : x + yev = c]

A: The given problem is to find the solution for the given differential equation. We can solve it by…

Q: e2x dx Find ex+1

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Q: ind dy/dx Y=x^2 e^x-xe^y^2

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Q: (3xy-x) dx + dy = 0

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Q: 4) dx + xdy = x²e dy

A: The given differential equation…

Q: arks] (a) Find d dx [1+ Hence evaluate 2x dx. (1+x²)²

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Q: > [2] S 1+e* dx 1-ex

A: The solution is given in the next step.

Q: Find -dx et + x-2 + C ex 1 + C 1 + C (1/2)x² e* e* – In |x| + C

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Q: 2 TC dx = X dx exactly. 5x 7. If find e+1 +1 12

A: Given,

Q: In3 x B. Evaluate ( [e2x+3y dy dx

A: We have to integrate

Q: 6 e + ex e dx et - 1

A: You have posted multiple questions.As per our policies , solving first question. Please ask the…

Q: Evaluate + 3e* dx A. 1+3e В. 1+ Зе +с C. In x +3e* + c

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Q: dy 2х dx e2y

A: Follow the procedure given below.

Q: 2- (2xe + e*)dx + (x² + 1)e'dy = 0 %3D

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Q: 4. (2xe" + e*)dx + (x² + 1)edy = 0.

A: Since you have asked multiple questions in a single request so we will be answering only first…

Q: 4. Compute the following: (a) e dx -1 d (Ъ) dx f'(x) dx a

A: 4.(a) The objective is to find the value of ∫-11edx

Q: 3. J - dx =? (x² + 1) (x + 2)

A: First we have to resolve the given expression by using partial fraction.

Q: (x – 1)2 dPy dx? – 2(x – 1): 2 + y = x + 4. dx -

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Q: 21. (x+ y)? dx + (2xy + x² – 1) dy = 0, y(1) = 1

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Q: 4) dx + xdy = x²e" dy %3D

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Q: e2x dx= 1+ex A ex – In(1+ e*) + C B e2x + In(1 + e*) + C © 2e2x – In(1+ e*) +C D e2х- in(1 + e*) + с

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Q: 2xy +1 x + 2y dy dx

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Q: 1 B (m,n) = 0. x-1 (1-x) n-'dx %3D

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Q: (d) / (2² + 1)² dx (e) L dx (x² + 1)² (f) ei* dx

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Q: - S (x+1)dx в с х-1 (х-1)?, A If (x+2)(x– 1)² dx , the values of A & C respectively are + %3! x+2

A: The given equation is as follows. Solve the function by partial fractions as follows.

Q: - dx 2. S e* + e*

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Q: e2x dx= 1+e* xp- e2x – In(1 + e*) + C e2x + -In(1+e*) + C B (C) ex – In(1+ e*) + C D 2e2x – In(1+…

A: The given integral ∫e2x1+exdx

Magnitude

A vector is an element with both direction and magnitude. A vector is represented using an arrow, where the arrow represents the direction of the vector and its length is represented using the magnitude. The set of vectors in space is known as vector space. The vectors can be added, subtracted, multiplied, and divided in a vector space. The image below shows a vector AB.