x? + y? = 4 and x? + y? = 4x Compute the area bounded by

Q: Determine the area bounded by x²=y-1 and x=y-3

A: To find: The area bounded by the region x2=y-1 and x=y-3. Formula used: The area under the curve…

Q: Find the area bounded by y=2/√16−4x^2, x=0, y=0, x=1. Round to four decimal places.

A:

Q: Find the area bounded by the following curves and lines: 4y = x^2 - 2ln(x), y=0, x=1, and x=4

A: SOLUTION-

Q: 4 Find the area bounded by Y 0, y = 0, x = 2. %3D /144 – 16x? Round to four decimal places.

A: We have to use definite integration.

Q: Determine the area bounded by y = x + 1 and y=1-x

A: If   x=fy be a continuous function of  y on a,b,then the area bounded by the curve x=fy and the…

Q: Solve for the area bounded by the graphs of y = √√x + 2, y = x + 2, x = 2, x = 4

A:

Q: Determine the area bounded by y= x< and y= 2x +3

A: We can find the area bounded by the graph and include the limits for finding the area bounded.

Q: Find the area bounded by : f(x)=e*, g(x)=e* and x=3.

A:

Q: Find the area bounded by the given curves and lines. 1 (2–æ)³ x = -2 х — о

A: The given curves are: y2=1(2-x)3x=-2x=0

Q: 3. Find the area bounded by the curve 2x² + 4x +y = 0 and y = 2x. Answer: 'n bs

A: Given:     curve 2x2+4x+y=0                and y=2x    2(x2+2x+1)=-y+2(1)    2(x+1)2=-(y-2)…

Q: Find the area bounded by the given curves and lines. 1 (2-2)3 x = -2 x = 0

A: This question is based on application of integration.

Q: 4y = x 2 – 2lnx, y = 0, x = 1, x = 4.

A:

Q: Find the area bounded by the given curves and lines. y? (2-a) x = -2 | x = 0

A:

Q: find the area bounded by the following curves and lines  y = 3x/square root of x+4  where y = 0 and…

A: The given region are: y=3xx+4, y=0, x=4

Q: Find the area bounded by y^2 = 2x + 3 and y = x. * y = x 4 3 -2 y? = 2x + 3

A: The equation of the curves are C1: y2 = 2x+3 ⇒ x = y2-32C2: y = x To evaluate: The area bounded by…

Q: 4 Find the area bounded by y = x = 0, y = 0, x = 4. V400 – 16x² Round to four decimal places.

A: The region is bounded by,y=4400-16x2, x=0, y=0, x=4

Q: Calculate the area bounded by y=x³, x=0 and y=3.

A:

Q: Compute the area bounded by the functions: 3y and x = y? - 10

A: From the given functions the bounded region is as shown below. Now find the point of intersection…

Q: find the area bounded by y=(1-x²) and y=0

A: Given curves are y=1-x2, y=0 The graph is as follows Here, yellow colored region is the required…

Q: What is the area bounded by y = x² and y =1– 3x2? Find an exact value. %3D

A:

Q: Find the area bounded by f(x)=x2-3x+7 and g(x)=2x+7. (round answer to two decimal places)

A: We need to find the area bounded by the curve.

Q: Find the area bounded by the curves over the interval. y = 3x? – 1, y = x – 2, -2 <x <1

A: The graph containing the regions y=3x2-1, y=x-2 in the interval -2≤x≤1 is shown below.

Q: Find the area bounded by the functions: f(x) = x^2 − 8x + 20, g(x) = 14 −x

A: Given functions:                           fx=x2-8x+20gx=14-x The graph drawn is The shaded region…

Q: Find the area bounded by y=4/√(400−16x^2), x=0, y=0, x=3. Round to four decimal places.

A:

Q: 3 Find the area Of the indicated region. between y=X and y= x2For x 'in

A:

Q: Find the area bounded by the given curves, axes and/or lines. 1. y2 + x – 4y = 5; y-axis

A: Note: As per our company guidelines we are supposed to answer the first question only. Kindly ask…

Q: 2 the area bounded by y = x , y = x is

A:

Q: 10. Find the area bounded by y = x and x? - 2x – y = 0.

A:

Q: Find the area under the graph of y = (x + 1)^-2for x ≥ 0.

A:

Q: Find the area bounded by x2 – 6x + y = 0 and y = x.

A:

Q: Find the area bounded by y = 4x - x² and y = x.

A: Topic : application of integration

Q: Find the area bounded by y(x + 2) = 1, x = 0, y = 0, and x = 4.

A:

Q: 8. Find the area in the first quadrant bounded by x = 0 using the most y=x², y = 2-x and appropriate…

A:

Q: Find the area bounded by the graphs of the indicated equations. Compute answers to three decimal…

A: The equation of the curves are: y = x3-3x2-27x+10 y = x+10 To evaluate: The area bounded by the…

Q: Find the area bounded by y = Round to four decimal places. 2 100 - 4x² x = 0, y = 0, x = 2.

A:

Q: 1. Find the area bounded by: x=y² and y=-x².

A:

Q: 4 Find the area bounded by Y = 0, y = 0, x = 2. || 144 – 16x² Round to four decimal places.

A:

Q: Find the area bounded by y = 2 - x squared and y = x

A:

Q: Find the area bounded by y = x2 and y = x+2.

A:

Q: Find the area bounded by y^2 = 2x + 3 and y = x. y = x y? = 2x +3

A:

Q: x? +y? = 4 and x² + y? = 4x 1) Compute the area bounded by

A: Given

Q: Solve for the area bounded by the graphs of y = √√√x + 2, y = x + 2, x = 2, x = 4

A: Graph:

Q: 3. Find the area bounded by y = x2 – 2x – 3 and y = x+ 1.

A: Calculus   -  area between two curves .

Q: Solve the area bounded by y^3+10=x^2, the lines y=-2 and y=2

A: Given: The curve is y3+10=x2 and lines are y=-2 and y=2 To find: Area

Q: FIND THE AREA BOUNDED BY THE FF CURVES AND LINES: The loop of y^2 = x^4 (4-x)

A: We have to find the area bounded by the loop  y2 = x4(4 - x)

Q: Find the area bounded by y = x³ – 3x and y = -4.

A: To find the area bouded by the curves.

Q: Find the area bounded by y = æ³ – 8, y = 0 and x 0.

A:

Q: Find the area bounded by x = y²- 2y and x =4 - y

A:

Optimization

Optimization comes from the same root as "optimal". "Optimal" means the highest. When you do the optimization process, that is when you are "making it best" to maximize everything and to achieve optimal results, a set of parameters is the base for the selection of the best element for a given system.

Integration

Integration means to sum the things. In mathematics, it is the branch of Calculus which is used to find the area under the curve. The operation subtraction is the inverse of addition, division is the inverse of multiplication. In the same way, integration and differentiation are inverse operators. Differential equations give a relation between a function and its derivative.

Application of Integration

In mathematics, the process of integration is used to compute complex area related problems. With the application of integration, solving area related problems, whether they are a curve, or a curve between lines, can be done easily.

Volume

In mathematics, we describe the term volume as a quantity that can express the total space that an object occupies at any point in time. Usually, volumes can only be calculated for 3-dimensional objects. By 3-dimensional or 3D objects, we mean objects that have length, breadth, and height (or depth).

Area

Area refers to the amount of space a figure encloses and the number of square units that cover a shape. It is two-dimensional and is measured in square units.