x.tan 2x - 2x.tan x pute Lt (1.cos 2x)

Q: tan e de (1+ In cos ele

A:

Q: S./2(sec²x – cos²?x – tan²x)sin5xcosxdx -

A:

Q: Iim tan³x X10 1- Cos2x

A:

Q: 2 cos² x√4 tan x S tan² x dx

A:

Q: Evaluate S(cos4 x – sin* x)dx

A:

Q: Evaluate f 1+cos 4x dx 1-cos 4x

A: To evaluate the given integral.

Q: 2. tan3x(sec3x – cos3x) dx

A:

Q: 9 sin5(x) cos³(x) dx

A:

Q: 5х, 5x sin°(cos* () dx 5 4 6 6

A:

Q: | sin(4z) cos(7z) dz.

A: To find:∫sin4zcos7zdz

Q: /2 sin 2x dx Jo 3+cos (2x)

A:

Q: Evaluate ∫sin2 x cos4 x dx.

A:

Q: = (a) Evaluate S cosx sinx V1 – sin4x dx. -

A: Given∫cosxsinx1-sin4xdx

Q: Cos 2x dx ) Sin*2× + 8 1.

A: Given ∫cos2xsin22x+8dx

Q: Evaluate (2 cos x-sin x)² -dx sin x

A: We have to solve the above integrals

Q: Solve f ) = (tanX + Cos x and t Cos X

A:

Q: Evaluate ∫sin 3x cos 5x dx

A: Given: I=∫sin3xcos5xdx                                                          ...1 for finding…

Q: 3. Find S sin5 x cos* x dx.

A: Use substitution method

Q: Find the first and second derivatives of r = [3 cos 2t, 3 sin 2t , 4t].

A:

Q: 2, " cos“(x)sin*(x)dx

A: To find : ∫0π2cos6xsin4xdx

Q: find solution set of tan-1x-cot-1x=cos-1(2-x)

A:

Q: Verify. esc (x) [I-cos(2x)] = 2 sin (x) SC

A:

Q: coS(T/11)-cos(2t/11)+cos(3t/11)-cos(4Tt/11)+cos(5rt/11)=?

A: To determine the value of the below expression. cosπ11−cos2π11+cos3π11−cos4π11+cos5π11

Q: Evaluate S (cos4 x – sin“ x) dx

A:

Q: Evaluate sin 3x cos 5x dx.

A:

Q: 2 2 | sin x cos xdx X,

A: As per our guidelines we are supposed to answer only one question kindly repost the other question…

Q: ind sin2x, cos 2x, and tan 2.x if tanx = -2 and x terminates in guadrant II. %3D sin 2x ? cos 2x tan…

A: In second quadrant sin is positive and cos & tan are negative.

Q: 2cosx dx 5- ? 2 1+(sinx)2

A:

Q: 7 cos2(x) tan3(x) dx

A:

Q: 4) Verify. cos²(x)[1 C. – tan²(x)] = cos(2x)

A:

Q: 2 , 1 + sinx +. D. cosx cosx il + sin.x

A:

Q: COS X dx 1-sin x

A:

Q: cOs Xx dx 4 + sin² x 9.

A: from the given data

Q: 12. sin 2t – tan t = tant cos 2t - HINT: You will use a reciprocal identity.

A: use the formula

Q: 2 tan(2x) − 4 cos(x) = 0

A: Explanation of the solution is given below.... And solve the given equation.....

Q: cos(2x) dx 2 (sin(2x)+5)*

A:

Q: Number 17

A: First we break sin^3 x in sin^2x*sin x, and then we replace sin^2 x by 1-cos^2 x.THen in the next…

Q: 2. Evaluate x sin x cos xdx.

A:

Q: Find:  ∫sin(3x) cos(6x) dx.

A: cos(2u) =2cos2u -1

Q: In(tan x) -dp- sin x cos X 3 4

A: To evaluate the given definite integral.

Q: = 2. If y = sin³ (-) cos³ (1) prove that y' = sin² (x) cos(x)

A: Topic = Derivative

Q: . Evaluate cos 3x sin² 3x dx

A:

Q: b- S sin5x.cos²x.dx

A:

Q: (B) Evaluate tan°(3x +1) sec³(3x +1) dx

A:

Q: Find sin (x/2) cos(x/2) tan(x/2)

A: Given information is :

Q: Find ∫sin 5x cos 4x dx.

A: Given, ∫sin5x.cos4xdx