x2-4x dx 3) S (x+1)(x²+4)

Q: 4x – 3 - 3 Given : | dx x² (x² + 9)

A: Given : ∫4x2-3x2x2+9dx

Q: x2-3x+1 i) S xln²xdx and ii) S7 dx. (x+2)(x2+1)

A: Given: ∫x ln2 (x) dxFormula: (ln (x))'=1x∫ x dx=x22+C

Q: 2 Find 2(x² + 3x - 1) xp- b. (x+ IX2x - 1)ar – 1)' dx x(x + 1) + 2 – 2x – x² a

A: We Use partial Fraction to separate the denominator and then integrate with respect to x.

Q: 17x-6 - dx x² -x² - 6x 2.

A:

Q: 9. Integral (2x-5) dx x²5x+3

A:

Q: –2x x- -dx x2+e-2r A (x-e-2r) x²+e-2x xp- B -2 (х—е -2) x²+e-2x xp- e -2r dx x²+e-2r x²+e -2x D E)…

A:

Q: (3x²-1) 5x3-5x+13 - dx equals In 15x³5x + 13| + c In 15x³ - 5x + c 5 O 1 In 15x³ - 5x + 13| + c 5 In…

A:

Q: f(x)dx = 2, 5 and 8 f(x)dx = -5, then, 8 f(x)dx = -3

A:

Q: x3-27 dx 2. ズ-3

A:

Q: 2x2-3х-1 -dx (x²+9)(x-5) E. Integrate:

A: Let's integrate.

Q: 27. ·√ √(x + 2√1-x²) dx _28. [₂ (2+√9 − x²) dx -3

A:

Q: (x²-2x+11)dx (x²+3x-4) .2. r2.

A:

Q: x²-3x - 7 √ - (x² + x + 2)(2x − 1) dx

A: Given: I=∫x2-3x-7x2+x+22x-1dx   As we know that; ∫1ax+bdx=1alnax+b+C

Q: 5. (3x-17) dx / (x² - 6x + 10) 11

A: As per our guide lines we are supposed to answer only one question. Kindly repost other questions as…

Q: x² - 2x x3 3x² - - dx -In 1x³ 3x² 1 + C Option 1 Option 3 - -In 1x³ 3x² 1 + C In 1x³ 3x²1+ C Option…

A: SOLUTION-

Q: 1) Evalvate - 5 dx ZV5 arctan x - 5 5 2 /5 arctan X-5 +C 2 x* - 5 arctan 5 arctan 25

A:

Q: 5 ,2 X |x² + x – 6| dx -5

A:

Q: x²-3x - 7 2 (x² + x + 2)(2x - 1) dx

A: Simplifying the given integrand: x2-3x-7(x2+x+2)(2x-1)=x2-3x-72(x2+x+2)x-12

Q: 1 x-3 x2-3x-4 dx

A:

Q: 2 1. x(-x² + 1) dx 16 dx 4x2 2. 3. dx x3/7 -V4x dx 4. 5. . (-2x! – x295) dx

A: According to the guidelines issued by the company We are supposed to answer only first three…

Q: x4 – 4x3 + 8x² – 13x + 13 dx - - (x – 1)(x2 + 4)

A:

Q: 4 (х -3)dx 4. x2 - 6х + 10 3.

A:

Q: f3xcos(4-x*)-8xV4=x² dx s(4-x²)-8x/4-x² dx —:

A: Let us solve the integral using substitution method in the next steps.

Q: 2-5x-x2 dx (x2-x-6)(x+2)

A: This question is based on indefinite integral.

Q: 5Tanx+13=2ZTanx Lineer (23inx+13)-(2605x)=0 CSCX-(secx-2)=0 Fackr 20033X +C05X-1=0 uva Quie…

A:

Q: X 4. f* - 2x² - 6x +1 2 x² - 2x-8 dx

A: We have to find the integral.

Q: x²-3x - 7 √(x² + x + 2) (2x - 1) dx

A:

Q: 5. Show that (x² + 1)e-* dx = -x²e-x – 2xe-x – 3e-x +C

A:

Q: In the function given. Evaluate the integrals.

A: Given:∫03 fx dx=2,∫36 fx dx=-5∫36 gx dx=1∫36 3 fx -gx dx=?

Q: • 4 13х + 12 -dx x2 + 3x 3

A: ∫3413x+12x2+3x-4dxApplying completion of squares:=∫3413x+12x+322-254dxSubs u =…

Q: 23-4x-8 Integrate: 2E+4) dx 1)(r²+4)

A:

Q: (-x³ + 3x² + 1) dx 2) (x* + x³ – 4x² + 6) dx -2 3) 12x + 13) dɔ 4) -x³ + 3x² – 2) dx

A: Follow the procedure given below.

Q: х — х* - 3х - 2 X | dx x* - x'+ 4x – 4x 3

A:

Q: x - 7 Integrate dx. x2 – 2x - 3

A: NOTE: Refresh your page if you can't see any equations. .

Q: by3 (3b² – x²)(1 – x5V3)/3b² – x² dx - -

A:

Q: x-3 dx V16-x² (16-х2

A: Given,          ∫x-316-x2dx

Q: 3. -2x-4 dx x-3 6x 4. (x2-7):/

A: (3).   The given integral is: ∫x3-2x2-4x-3dx

Q: (3z² + 1) dx (2 + 2x + 1)²

A:

Q: 6. S (2x+3) dx (x2+3x-6)9

A:

Q: 4x3-3x+5 If 13x+5 dx , then f (0) = x²-2x x²-2x,

A: Given : ∫4x3-3x+5x2-2xdx=∫fx+13x+5x2-2xdx Objective is to find the fx and then value of fx at x=0

Q: 4 -4 x3 16-x² dx is equal to

A:

Q: x-2 x² - 4x-9 -dx

A:

Q: ~10 xe Ax) = Sg" -dx (x + 2)(x+3)(,² – 1)

A: The given problem is evaluate the given definite integral using Simpsons 3/8 rule.

Q: x² +x-2 -dx can be resolved into (x2-1)(2x-x²)

A:

Q: 6-6r dx x-3x -2 In|x3 – 3x| + C In|x3 - 3x| + C -1 +C 3(x³ – 3x)

A: The detailed solution is given below Thank you

Q: 3. (a) Determine 3 4 dx VI - x², + x2 (b) Determine 3 + V1- x2 4 dx 1+ x2

A:

Q: 10x-25 -dx x²–3x-4

A:

Q: 3 2 - VX dx x² – 4 1 2]

A: ∫12xx2-43dxLet u=x2-4.=∫-3012u3du=12·∫-301u3du=1232u23-30=12--123· 323·32=-3-123· 3234

Q: (х2-2х+11)dx (x2+3х-4) .2.

A: