x2-9 If f(x) = then f (x) discontinuous at x= 3 because..... x-3 x2-9 Jika f(x) = fungsi f (x) diskontinu di x= 3 karena.….... x-3 lim f (x) does not exist x→3 lim f(x) tidak ada X→3 1. O 2. O f(3) exists. f(3) terdefinisi. lim f (x) f(3) x→3 3. О 4. O f(3) is undefined. f(3) tidak terdefinisi.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
x²-9
If f(x) =
then f (x) discontinuous at x = 3 because.....
X-3
x²-9
Jika f(x) =
fungsi f (x) diskontinu di x= 3 karena....
X-3
lim f (x) does not exist
x→3
lim f (x) tidak ada
X→3
1. O
2. O f(3) exists.
f(3) terdefinisi.
lim f (x)
f (3)
x→3
3. O
4. O f(3) is undefined.
f(3) tidak terdefinisi.
Transcribed Image Text:x²-9 If f(x) = then f (x) discontinuous at x = 3 because..... X-3 x²-9 Jika f(x) = fungsi f (x) diskontinu di x= 3 karena.... X-3 lim f (x) does not exist x→3 lim f (x) tidak ada X→3 1. O 2. O f(3) exists. f(3) terdefinisi. lim f (x) f (3) x→3 3. O 4. O f(3) is undefined. f(3) tidak terdefinisi.
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