mov edx,1 mov eax,7FFFh
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- Please do this question through https://cpulator.01xz.net/?sys=arm-de1soc Assembly language using ARM Write an assembly language program that uses 3 registers. R0,R1 and R2 . The registers should have values 2, 5, and 0, respectively. The program will add, sub, divide and multiply the contents of the Register R0 to that of R1 and store the result into R3.The following assembly language intruction contains ERRORS: Line 1 MOV 23,AX Line 2 MOVE TOTAL,BX Line 3 MOV IP, DX Line 4 MOV AX, DL Line 5 DIV AL, CL What are the errors? identify and write the correct instuctions.Microprocessor 8086 Code Mov 0058H ,04H Mov 0053H,06H So when I calculate physical address in formula Ds*10+offset address I get my Ds indicates 3000 So 3000*10+0058=30058 physical address When try to find 30058 in the memory location in emu8086 I couldn’t find this physical address in the memory but I see another address is that I am wrong in this way What want to do is When go to 30058 physical address in this address to value of 04H on its data a m wrong?
- VMware and VirtualPC execute all x86 instructions in the exact same manner as a real x86 CPU would Group of answer choices True Falsemicroprocessor 8086/8088 which one and how ? Assume the content of the segment register ES = ACEE H, the possible value for segment register CS= ? CS=B822H CS=A215H CS-ACEEH CS=2ED5HSubject: Assembly Language Q: What will be the final value of EAX in this example? mov eax, 0 mov ecx, 10 L1: mov eax, 3 mov ecx, 5 L2: add eax, 5 loop L2 loop L1
- Explain the interfacing operation of 8259A with 8086 system? Write the Operation command word formats (OCW1, OCW2 & OCW3) of 8259A.The MSP430 can move/copy a byte or a word at a time using the instructions mov.b and mov.w respectively. In particular, the instructions mov.b &source_address, R4 mov.w &source_address, R4 copy the byte or word that resides at the given address (&source_address) to the given destination (the core register R4 in the CPU). Which of the following instructions are valid? (a) mov.b &0x1C03, R4 (b) mov.w &0x1C02, R4 (c) mov.b &0x1C00, R4 (d) mov.w &0x1C05, R4using the tasm syntax (intel style), write a x86 assembly code that does the following tasks: (a) add two groups of numbers using the loop instruction, 1 + 3 + 5 + ... + 99 2 + 4 + 6 + ... + 100 (b) print the two results on the screen. (c) the code must be assembled/built/run successfully with the gui_tasm software
- Rearrange the steps for X86 interrupt processing: a. Save current processor status word (condition codes) b. Switch to kernel mode c. Interrupt handler saves registers it might clobber d. Save current program counter e. Switch to kernel stack; put SP, PC, PSW on stack f. Vector through interrupt table g. Save current stack pointer1- What is the X86 architecture family of the Intel? 2- What is the proposed work that the authors were trying to implement by doing their study? 3- Discuss the performance of 8086 microprosseors identified by the author of paper? 4- What is floating point number? How 8086 prossors improve floating point computation performance. 5- Discuss various feature of 8086 CPU as identified by the authors.Which of the following two systems is better?• A program is converted into 4 billion MIPS instructions by acompiler ; the MIPS processor is implemented such thateach instruction completes in an average of 1.5 cycles andthe clock speed is 1 GHz• The same program is converted into 2 billion x86 instructions;the x86 processor is implemented such that each instructioncompletes in an average of 6 cycles and the clock speed is1.5 GHz