Xg is an antigen found on red blood cells. This antigen is caused by an Xlinked allele (Xa) that is dominant over an allele for the absence of the antigen (X–). The inheritance of these X-linked alleles was studied in children with chromosome abnormalities to determine where nondisjunction of the sex chromosomes took place. For each type of mating in parts a through d, indicate whether nondisjunction took place in the mother or in the father and, if possible, whether it took place in meiosis I or meiosis II (assume no crossing over). a. XaY × X-X- → Xa(Turner syndrome) b. XaY × XaX- → X- (Turner syndrome) c. XaY × XaX- → X- X- Y (Klinefelter syndrome) d. XaY × XaX- → X- X-Y (Klinefelter syndrome)

Xg is an antigen found on red blood cells. This antigen is caused by an Xlinked allele (Xa) that is dominant over an allele for the absence of the antigen (X–). The inheritance of these X-linked alleles was studied in children with chromosome abnormalities to determine where nondisjunction of the sex chromosomes took place. For each type of mating in parts a through d, indicate whether nondisjunction took place in the mother or in the father and, if possible, whether it took place in meiosis I or meiosis II (assume no crossing over). a. XaY × X-X- → Xa(Turner syndrome) b. XaY × XaX- → X- (Turner syndrome) c. XaY × XaX- → X- X- Y (Klinefelter syndrome) d. XaY × XaX- → X- X-Y (Klinefelter syndrome)

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Description: Xg is an antigen found on red blood cells. This antigen is caused by an Xlinked allele (Xa) that is dominant over an allele for the absence of the antigen (X–). The inheritance of these X-linked alleles was studied in children with chromosome abnorma

Human Biology (MindTap Course List)

11th Edition

ISBN:9781305112100

Author:Cecie Starr, Beverly McMillan

Publisher:Cecie Starr, Beverly McMillan

Chapter20: Chromosomes And Human Genetics

Section: Chapter Questions

Problem 2CT: Human sex chromosomes are XX for females and XY for males. a. With respect to an X-linked gene, how...

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Human sex chromosomes are XX for females and XY for males. a. With respect to an X-linked gene, how many different types of gametes can a male produce? b. If a female is homozygous for an X-linked allele, how many different types of gametes can she produce with respect to this allele? c. If a female is heterozygous for an X-linked allele, how many different types of gametes can she produce with respect to this allele?
Xg is an antigen found on red blood cells. This antigen is caused by an Xlinked allele (Xa) that is dominant over an allele for the absence of the antigen (X–). The inheritance of these X-linked alleles was studied in children with chromosome abnormalities to determine where nondisjunction of the sex chromosomes took place. For each type of mating in parts a through d, indicate whether nondisjunction took placein the mother or in the father and, if possible, whether it took place in meiosis I or meiosis II (assume no crossing over). Q. XaY × X-X- → Xa(Turner syndrome)
Xg is an antigen found on red blood cells. This antigen is caused by an Xlinked allele (Xa) that is dominant over an allele for the absence of the antigen (X–). The inheritance of these X-linked alleles was studied in children with chromosome abnormalities to determine where nondisjunction of the sex chromosomes took place. For each type of mating in parts a through d, indicate whether nondisjunction took placein the mother or in the father and, if possible, whether it took place in meiosis I or meiosis II (assume no crossing over). Q. XaY × XaX- → X- (Turner syndrome)
Xg is an antigen found on red blood cells. This antigen is caused by an Xlinked allele (Xa) that is dominant over an allele for the absence of the antigen (X–). The inheritance of these X-linked alleles was studied in children with chromosome abnormalities to determine where nondisjunction of the sex chromosomes took place. For each type of mating in parts a through d, indicate whether nondisjunction took placein the mother or in the father and, if possible, whether it took place in meiosis I or meiosis II (assume no crossing over). Q. XaY × XaX- → X- X- Y (Klinefelter syndrome)
Suppose gene B is X-linked and is embryonically lethal when homozygous or hemizygous recessive. A man marries a woman who is heterozygous for this gene. They want to have three kids – one girl and two boys. Using a Punnett square, answer the following: What is the probability that they will have a son that dies before birth? _______________________ What is the probability that they will have a daughter who has the same genotype as her mother? _________________ One of their daughters eventually has a child with a man. One of their sons dies before birth. What was the genotype of this daughter? _______________________________ please show me how to get the answer and explain how you got and use a punnet square
In beetles, an X-linked gene determines body size, with normal size (M)completely dominant to miniature body size (m). Body color is determined by an autosomal gene with two alleles, where B is incompletely dominant to b such that BB beetles are black, Bb beetles are brown and bb beetles are yellow. Male beetles are heterogametic (XY). The following cross is performed: brown, miniature sized body female X brown, normal sized body male Based on this information, which of the following statements is FALSE? Select 3 correct answer(s) Question 3 options: A) 1/8 of the female progeny will have yellow miniature bodies. B) All of the male progeny will have miniature bodies. C) 1/4 of the total progeny will be black. D) 1/4 of the male progeny will have yellow miniature bodies. E) All of the female progeny will have miniature bodies.…
In fruit flies, eye color is carried on the X chromosome. The allele for red eyes is dominant over its recessive allele, white eyes. -Cross a heterozygous female to a white-eyed male 1st Question to answer ---- How many genotypes are possible among the offspring? 2nd Question to answer ---- How many phenotypes are possible among the offspring? 3rd Question to answer ---- What is the probability of getting a red-eyed male? 4th Question to answer ---- What is the probability of getting a white-eyed male? 5th Question to answer ---- What is the probability of getting a red-eyed female? 6th Question to answer ---- What is the probability of getting a white-eyed female? 7th Question to answer ---- What is the probability of getting a red-eyed offspring? 8th Question to answer ---- What is the probability of getting a white-eyed offspring?
A gene that controls the ability to see red and green is located on the X chromosome but not on the Y chromosome. There is a recessive nonfunctional allele for this gene that can cause red-green color blindness if the person possessing it does not also have the dominant normal gene. Consider the case of a carrier mother who is heterozygous for the red-green vision gene and a father who has normal vision. Use XB = normal vision, Xb = color-blind vision. What is the chance the parents would have a color-blind boy? A color-blind girl? What about a girl or boy with normal vision? Redo the Punnett square for a carrier mother (XBXb) and a color-blind father (XbY). Do the chances of having color-blind children change? How?
In humans, the ABO blood type is under the control of autosomal multiple alleles. Color blindness is a recessive X-linked trait. If two parents who are both type A and have normal vision produce a son who is color-blind and is type O, what is the probability that their next child will be a female who has normal vision and is type O?
Red-green color blindness is inherited as an X-linked recessive (Xc). If a color-blind man marries a woman who is heterozygous for normal vision, what would be the expected phenotypes of their children with reference to this character? In your answer, specify in your phenotype descriptions the gender of the children. (For example, don’t just say 75% of the children would be colorblind – you would instead say 100 % of the daughters would be colorblind and 50% of the sons would be colorblind. Note that this is not a correct answer; it is just to give you an idea of how to explain the correct phenotypes of the cross.)___
The most common form of colorblindness is a recessive, sex-linked hereditary con dition caused by a defect on the X chromosome. Females are XX, while males are XY. Individuals inherit one chromosome from each parent, with equal probability; for example, an individual has a 50% chance of inheriting their father's X chromosome, and a 50% chance of inheriting their father's Y chromosome. If a male has an X chromosome with the defect, he is colorblind. However, a female with only one defective X chromo some will not be colorblind. Thus, colorblindness is more common in males than females; 7% of males are colorblind but only 0.5% of females are colorblind. (a) Assume that the X chromosome with the wild-type allele is X+ and the one with the disease allele is X. What is the expected frequency of each possible female genotype: X+X+, X+X¯, and X-X-? What is the expected frequency of each possible male genotype: X+ Y and X-Y? (b) Suppose that two parents are not colorblind. What is the…
A type of red-green colorblindness is inherited recessively on the X chromosome. A woman who is a carrier had children with a male that is not affected by the disease. Show your answers with the use of a Punnett square • What is the probability (% or likelihood) that a child is affected by the disease? • What is the probability (% or likelihood) that a son is a carrier? (Careful!) • Is there a chance that a girl of the couple is affected by the disease?